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  • In the last video, we found the slope at a particular point of

  • the curve y is equal to x squared.

  • But let's see if we can generalize this and come up

  • with a formula that finds us the slope at any point of the

  • curve y is equal to x squared.

  • So let me redraw my function here.

  • It never hurts to have a nice drawing.

  • So that is my y-axis.

  • That is my x-axis right there.

  • My x-axis.

  • Let me draw my curve.

  • It looks something like that.

  • You've seen that multiple times.

  • This is y is equal to x squared.

  • So let's be very general right now.

  • Remember, if we want to find-- let me just write the

  • definition of our derivative.

  • So if we have some point right here-- let's call that x.

  • So we want to be very general.

  • We want to find the slope at the point x.

  • We want to find a function where you give me an x

  • and I'll tell you the slope at that point.

  • We're going to call that f prime of x.

  • That's going to be the derivative of f of x.

  • But all it does is, look, f of x, you give-- it's a function

  • that you give it an x, and it tells you the value of that.

  • And we draw the curve here.

  • With f of x, you give that same x but it's not going to tell

  • you the value of the curve.

  • It's not going to say, oh, this is your f of x.

  • It's going to give you the value of the slope of

  • the curve at that point.

  • So f of x, if you put it into that function, it should tell

  • you, oh, the slope at that point, is equal to-- you know,

  • if you put 3 there, you'll say, oh, the slope there

  • is equal to 6.

  • We saw that in the last example.

  • So that's what we want to do.

  • And we saw on the last-- I think it was 2-- videos ago,

  • that we defined f prime of x to be equal to-- just the--

  • well, I'll write it this way.

  • It's the slope of the secant line between x and some

  • point that's a little bit further away from x.

  • So the slope of the secant line is change in y.

  • So it's the y value of the point that's a little

  • bit further away from x.

  • So f of x plus h minus the y value at x, right?

  • Because this is right here.

  • This is f of x.

  • So minus f of x.

  • All of that over the change in x.

  • So if this is x plus h here, the change in x

  • is x plus h minus x.

  • Or this distance right here is just h.

  • The change in x is going to be equal to h.

  • So that's just slope of the secant line, between

  • any 2 points like that.

  • And we said, hey, we could find the slope of the tangent line

  • if we just take the limit of this as it approaches--

  • as h approaches 0.

  • And then we'll be finding the slope of the tangent line.

  • Now let's apply this idea to a particular function, f of

  • x is equal to x squared.

  • Or y is equal to x squared.

  • So here, we could have the point-- we could consider this

  • to be the point x-- x squared.

  • So f of x is just equal to x squared.

  • And then this would be the point-- let me do it in

  • a more vibrant color.

  • This is the point x plus h-- that's this point right here.

  • It's a little bit further down.

  • And then x plus h squared.

  • And you know, in the last video, we did this

  • for a particular x.

  • We did it for 3.

  • But now I want a general formula.

  • You give me any x and I won't have to do what I did in the

  • last video for any particular number.

  • I'll have a general function.

  • You give me 7, I'll tell you what the slope is at 7.

  • You give me negative 3, I'll tell you what the slope

  • is at negative 3.

  • You give me 100,000, I'll tell you what the

  • slope is at 100,000.

  • So let's apply it here.

  • So we want to find the change in y over the change in x.

  • So first of all, the change in y is this guy's y value,

  • which is x plus h squared.

  • That's this guy's y value right here.

  • That's this right here.

  • That's x plus h squared.

  • I just took x plus h, evaluated, I squared it, and

  • that's its point on the curve.

  • So it's x plus h squared.

  • So that's there right there.

  • And then what's this value?

  • f of x right here is equal to-- I know it's getting messy--

  • is equal to x squared.

  • If you take your x, you evaluate the function

  • at that point, you're going to get x squared.

  • So it's equal to minus x squared.

  • This is your change in y.

  • That's this distance right there.

  • And just to relate it to our definition of a derivative,

  • this blue thing right here is equivalent to this

  • thing right here.

  • We just evaluated our function.

  • Our function is f of x is equal to x squared.

  • We just evaluated when x is equal to x plus h.

  • So if you have to square it, if I put an a there,

  • it'd be a squared.

  • If I put an apple there, it'd be apple squared.

  • If I put an x plus h in there, it's going to

  • be x plus h squared.

  • So this is that thing.

  • And then, this thing right here is just the function evaluated

  • at the point in question.

  • Right there.

  • So this is our change in y.

  • And let's divide that by our change in x.

  • Our change in x-- if this is x plus h and this is just x, our

  • change in x is just going to be h.

  • So that's where we get that term from.

  • So this is just a slope between these 2 points.

  • This is just a slope between those two points.

  • But, of course, we want to find-- the limit at this point

  • gets closer and closer to this point, and this point gets

  • closer and closer to that point.

  • So this becomes a tangent line.

  • So we're going to take the limit as h approaches 0, and

  • this is our f prime of x.

  • And this is the exact same definition of this, instead

  • of being general and saying, for any function, we know

  • what the function was.

  • It was f of x is equal to x squared.

  • So we actually applied it.

  • Instead of f of x, we wrote x squared.

  • Instead of f of x plus h, we wrote x plus h squared.

  • So let's see if we can evaluate this limit.

  • So this is going to be equal to the limit as h approaches

  • 0 to square this out.

  • I'll do it in the same color.

  • That's x squared plus 2xh plus h squared, and then we have

  • this minus x squared over here.

  • I just multiplied this guy out over here.

  • And then all of that is divided by h.

  • Now let's see if we can simplify this a little bit.

  • Well, you immediately see you have an x squared and you

  • have a minus x squared, so those cancel out.

  • And then we can divide the numerator and the

  • denominator by h.

  • So this simplifies to-- so we get f prime of x is equal to--

  • if we divide the numerator and the denominator by h--

  • we get 2x plus h.

  • I'm sorry, I forgot my limit.

  • It equals the limit.

  • Very important.

  • Limit as h approaches 0 of divide everything by h, and

  • you get 2x plus h squared divided by h is h.

  • And if you remember the last video, when we did it with a

  • particular x, we said x is equal to 3, we got 6

  • plus delta x here.

  • Or 6 plus h here, so it's very similar.

  • So if you take the limited h approaches 0 here, that's

  • just going to disappear.

  • So this is just going to be equal to 2x.

  • So we just figured out that if f of x-- this is a big result.

  • This is exciting!

  • That if f of x is equal to x squared, f prime

  • of x is equal to 2x.

  • That's what we just figured out.

  • And I wanted to make sure you understand

  • how to interpret this.

  • f of x, if you give me a value, is going to tell you the value

  • of the function at that point.

  • At prime of x it's going to tell you the

  • slope at that point.

  • Let me draw that.

  • Because this is a key realization.

  • And you might, you know, it's kind of maybe initially

  • unintuitive to think of a function that gives us the

  • slope, at any point, of another function.

  • So it looks like this.

  • Let me draw a little neater than that.

  • Ah, it's still not that neat.

  • That's satisfactory.

  • Let me just draw it in the positive coordinate.

  • Well, I'll just draw the whole-- the curve looks

  • something like that.

  • Now this is the curve of f of x.

  • This is the curve of f of x is equal to x squared.

  • Just like that.

  • So if you give me a point.

  • You give me the point 7.

  • You apply, you put it in here, you square it.

  • And it is mapped to the number 49.

  • So you get the number 49 right there.

  • This is the number 7, 49.

  • You're used to dealing with functions right there.

  • But what is f prime of 7?

  • f prime of 7.

  • You say, 2 times 7 is equal to 14.

  • What is this 14 number here?

  • What is this thing?

  • Well, this is the slope of the tangent line

  • at x is equal to 7.

  • So if I were to take that point and draw a tangent line-- a

  • point that just grazes our curve-- if I were to just

  • draw a tangent line.

  • That wasn't tangent enough for me.

  • So that's my tangent line right there.

  • You get the idea.

  • The slope of this guy-- you do your change in y over your

  • change in x-- is going to be equal to 14.

  • The slope of the curve at y is equal to 7-- is

  • a pretty steep curve.

  • If you wanted to find the slope, let's say that this

  • is y-- let's say it's x is equal to 2.

  • I said at x is equal to 7, the slope is 14.

  • At x is equal to 2, what is the slope?

  • Well, you figure out f prime of 2, which is equal to 2 times

  • 2, which is equal to 4.

  • So the slope here is 4.

  • You could say m is equal to 4. m for slope.

  • What is f prime of 0?

  • f prime.

  • We know that f of 0 is 0, right?

  • 0 squared is 0.

  • But what is f prime of 0?

  • Well, 2 times 0 is 0.

  • That's also equal to 0.

  • But what does that mean?

  • What's the interpretation?

  • It means the slope of the tangent line is 0.

  • So a 0 sloped line looks like this.

  • Looks just like a horizontal line.

  • And that looks about right.

  • A horizontal line would be tangent to the

  • curve at y equals 0.

  • Let's try another one.

  • Let's try the point minus 1.

  • So let's say we're right there. x is equal to minus 1.

  • So f of minus 1, you just square it.

  • Because we're dealing with x squared.

  • So it's equal to 1.

  • That's that point right there.

  • What is f prime of minus 1?

  • f prime of minus 1 is 2 times minus 1.

  • 2 times minus is minus 2.

  • What does that mean?

  • It means that the slope of the tangent line at x is equal to

  • 1, to this curve, to the function, is minus 2.

  • So if I were to draw the tangent line here-- the tangent

  • line looks like that-- and look, it is a downward

  • sloping line.

  • And it makes sense.

  • The slope here is equal to minus 2.

In the last video, we found the slope at a particular point of

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The derivative of f(x)=x^2 for any x | Taking derivatives | Differential Calculus | Khan Academy

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    yukang920108 に公開 2022 年 07 月 12 日
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