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  • - [Voiceover] We're told that the tangent line to the graph

  • of function at the the point two comma three

  • passes through the point seven comma six.

  • Find f prime of two.

  • So whenever you see something like this,

  • it doesn't hurt to try to visualize it.

  • You might want to draw it out or just visualize it

  • in your head

  • but since you can't get in my head,

  • I will draw it out.

  • So let me

  • draw the information that they are giving us.

  • So that's x axis and that is the y axis.

  • Let's see the relevant points here at two comma three

  • and seven comma six.

  • So let me go,

  • one, two, three, four,

  • five, six, seven, along the x axis

  • and I'm going to go one, two, three, four,

  • five, and six, along the y axis.

  • And now this point,

  • so we have the point two comma three,

  • so let me mark that,

  • so two comma three is right over there,

  • so that's two comma three and we also have

  • the point seven comma six.

  • Seven comma six is going to be right over there.

  • Seven comma six.

  • Let us remind ourselves what they're saying.

  • They're saying the tangent line to the graph of function f

  • at this point

  • passes through the point seven comma six.

  • So if it's the tangent line to the graph at that point,

  • it must go through two comma three,

  • that's the only place where it intersects our graph

  • and it goes through seven comma six.

  • We only need two points to define a line

  • and so the tangent line is going to look like,

  • it's going to look like,

  • let me see if I can,

  • no that's not right.

  • Let me draw it

  • like it's going to look.

  • Oh that's not exactly right.

  • Let me try one more time.

  • Okay, there you go.

  • So the tangent line is going to look like that.

  • It goes, it's tangent two f right at two comma three

  • and it goes through the point seven comma six

  • and so we don't know anything other than f

  • but we can imagine what f looks like.

  • Our function f could,

  • so our function f,

  • it could look something like this.

  • It just has to be tangent

  • so that line has to be tangent to our function

  • right at that point.

  • So our function f could look something like that.

  • So when they say, find f prime of two,

  • they're really saying,

  • what is the slope of the

  • tangent line when x is equal to two?

  • So when x is equal to two,

  • well the slope of the tangent line

  • is the slope of this line.

  • They gave us, they gave us the two points that sit

  • on the tangent line.

  • So we just have to figure out its slope

  • because that is going to be the rate of change of

  • that function right over there,

  • its derivative.

  • It's going to be the slope of the tangent line

  • because this is the tangent line.

  • So let's do that.

  • So as we know,

  • slope is change in y over change in x.

  • So if we change our,

  • to go from two comma three to seven comma six,

  • our change in x,

  • change in x,

  • we go from x equals two to x equals 7

  • so our change in x is equal to five.

  • And our change in y,

  • our change in y,

  • we go from y equals three to y equals six.

  • So our change in y is equal to three.

  • So our change in y over change in x

  • is going to be three over five

  • which is the slope of this line,

  • which is the derivative of the function at two

  • because this is the tangent line at x equals two.

  • Let's do another one of these.

  • For a function g,

  • we are given that g of negative one equals three

  • and g prime of negative one is equal to negative two.

  • What is the equation of the tangent line to the graph of g

  • at x equals negative one?

  • Alright, so once again

  • I think it will be helpful to graph this.

  • So

  • we have our y axis,

  • we have our x axis

  • and let's see.

  • We say for function g we are given that g of negative one

  • is equal to three.

  • So the point negative one comma three is on our function.

  • So this is negative one and then we have,

  • one,

  • two,

  • and three.

  • So that's that right over there.

  • That is the point.

  • That is the point negative one comma three,

  • it's going to be on our function.

  • And we also know that g prime of negative one

  • is equal to negative two.

  • So the slope of the tangent line

  • right at that point on our function

  • is going to be negative two.

  • That's what that tells us.

  • The slope of the tangent line,

  • when x is equal to negative one is equal to negative two.

  • So I could use that information

  • to actually draw the tangent line.

  • So let me see if I can,

  • let me see if I can do this.

  • So it will look,

  • so I think it will,

  • let me just draw it like this.

  • So it's going to go,

  • so it's a slope of negative two

  • is going to look something like that.

  • So as we can see if we move positive one in the x direction,

  • we go

  • down two in the y direction.

  • So that is a slope of negative two.

  • And so you might say well, where is g?

  • Well we could draw what g could look like.

  • G might look something like this.

  • Might look something like that right over there

  • where that is the tangent line

  • or you can make g do all sorts of crazy things after that

  • but all we really care about is equation

  • for this green line.

  • And there's a couple of ways that you could do this.

  • You could say, well look a line is generally,

  • there's a bunch of different ways where you can define

  • the equation for a line.

  • You could say

  • a line has a form y is equal to mx plus b

  • where m is the slope and b is the y intercept.

  • Well we already know what the slope of this line is.

  • It is negative two.

  • So we could say y is equal to negative two.

  • Negative two times x.

  • Times x plus b.

  • And then to solve for b,

  • we know that the point negative one comma three

  • is on this line

  • and this goes back to some of your Algebra I

  • that you might have learned a few years ago.

  • So let's substitute negative one and three for x and y.

  • So when y

  • is equal to three,

  • so three,

  • three is equal to,

  • is equal to negative two,

  • negative two times x.

  • Times negative one,

  • times negative one plus b.

  • Plus b.

  • And so let's see,

  • this is negative two times negative one is positive two.

  • And so if you subtract two from both sides,

  • you get one is equal to b.

  • And there you have it.

  • That is equation of our line.

  • Y is equal to negative two x plus one.

  • And there's other ways that you could have done this,

  • you could have written the line in point-slope form

  • or you could have done it this way.

  • You could have written it in standard form

  • but at least this is the way my brain likes to process it.

- [Voiceover] We're told that the tangent line to the graph

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B1 中級

The derivative & tangent line equations | Derivatives introduction | AP Calculus AB | Khan Academy

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    yukang920108 に公開 2022 年 07 月 12 日
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