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- [Instructor] In this video,
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we're going to introduce ourselves
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to the idea of photoelectron spectroscopy.
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It's a way of analyzing the electron configuration
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of a sample of a certain type of atom.
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And so what you'll often see
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and you might see something like this on an exam,
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is a photoelectron spectrum
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that looks something like this.
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And so the first question is,
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well, what's even going on?
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How is this generated?
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Well, I'm not gonna go into the details,
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but the big picture is
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the analysis will be done by taking a stream of that atom,
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and so that atom, there's an atom stream
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going in one direction,
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and then the other direction, let me label this,
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so that's the atoms
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that we're trying to analyze,
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and then the other direction,
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you send high-energy photons
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that are going to bombard those atoms, photons.
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Now these photons are high enough energy,
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in fact, they're typically x-ray photons
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so that when they collide,
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the photons are high enough energy
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to overcome the binding energy
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of even the core electrons
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and as those electrons get knocked out,
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they move away
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and they enter into a magnetic field
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that will deflect those electrons
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and then make them hit a detector.
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And so you can imagine
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the electrons that are closer to the nucleus,
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those have the highest binding energy,
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and so more of that energy from the photon
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is going to be used to knock it off
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so less of it is going to be there
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for the kinetic energy,
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so those closer electrons aren't going to get as far
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and the outer electrons,
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those have the lowest electron binding energy.
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They're the easiest to knock off
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and so you have more of the photon's energy
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is going to be transferred into kinetic energy.
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And so they're going to get further away
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and they're going to hit the detector
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at a further point.
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And so one way to view the photoelectron spectrum
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is it gives you a sense of roughly how many electrons
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have various binding energies.
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And you can see that the binding energy increases
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as we go to the left.
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Now the reason why this makes sense,
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the binding energy is inversely proportional
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to how much kinetic energy these electrons have
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as they actually get knocked off.
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And so this spike on our spectrum at the extreme left,
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these are the innermost electrons,
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and then these would be electrons further out
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with the next lower binding energy,
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and then lower binding energy after that.
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And so we can analyze this
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to actually come up with the electron configuration
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of this mystery element right over here.
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What do you think that would be?
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Pause this video and try to think about that.
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Well as I mentioned,
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this spike right over here would correspond
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to detecting the innermost electrons,
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and so the innermost electrons
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are the one S electrons,
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and we know that those aren't the only electrons
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'cause there's electrons that have lower binding energies,
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and so we know that would have filled up
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that innermost shell
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and so we know that they have two one S electrons
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and then we can then think that this next spike,
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that's going to be the two S electrons
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and we have more electrons than that
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so we must have filled up the two S sub shell
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and then this next spike,
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this looks like two P.
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And the reason why this really makes a lot of sense is
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notice the detector is detecting more electrons there,
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and we also have more electrons,
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and so that must have been filled
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and that makes sense,
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and actually the way this was constructed,
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it's not always going to be this perfect,
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but you can see you have roughly three times as many two P
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electrons as two S electrons, which makes sense.
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The two P sub shell can fit six electrons.
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Two S sub shell fits two.
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So this next spike is going
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to be the next highest energy shell,
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which is going to have a lower binding energy.
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It's easy to knock the,
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it's easier to knock those electrons off.
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And so this looks like it's going to be the three S two
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and then this next spike,
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this looks like three P six
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and then that one gets completely filled
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and we have one more spike after that
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and that spike seems to get roughly the same number
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of electrons as all of the other S sub shells
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and we know from the Aufbau principle
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that the next we fill is four S
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and it looks like there's two electrons there
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because this spike is about the same
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as the other filled S sub shells.
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And so just like that,
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we're able to use a photoelectron spectrum
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to come up with the electron configuration
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of this mystery element.
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Its electron configuration is one S two,
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two S two,
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two P six,
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three S two,
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three P six,
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four S two.
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And what element has this electron configuration?
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Well, we've worked on it in other videos,
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but I can get my periodic table of elements out,
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and we can see, let's see.
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One S two gets us to helium,
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then you have two S two, two P six gets us to neon.
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Three S two, three P six gets us to argon,
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and then four S two gets us to calcium.
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So our mystery element is
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calcium,
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and if someone were to ask about valence electrons,
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that would be this outermost spike right over here.
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The spike of electrons with the lowest binding energy.
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They have the lowest binding energy
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because they're the furthest out there.
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They are the easiest to knock off,
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and because they're the easiest to knock off,
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most of that photon energy is leftover
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after overcoming the binding energy
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that gets converted into kinetic energy.
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So those electrons get deflected further.
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And the base of what we see here
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are the photoelectron spectrum of calcium.
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What would we expect the photoelectron spectrum
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of potassium be?
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And just as a reminder,
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potassium has an atomic number of 19,
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so it has 19 protons in the nucleus,
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while calcium has 20 protons in the nucleus,
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and we're going to assume
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that we're talking a neutral potassium atom,
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so it's going to have 19 electrons, as well.
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Pause this video and think about
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how it might be different.
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When we think about potassium,
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it's going to have a very similar photoelectron spectrum
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as calcium,
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but because it only has 19 versus 20 protons,
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it has less positive charge in the nucleus,
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so it pulls a little bit less hard
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on our various shells.
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So in potassium,
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you're still going to have one S two,
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but it's going to have a slightly lower binding energy
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because it's not pulled into the nucleus as much.
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And I'm not drawing it perfectly.
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It might not be this much.
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Actually, you know what?
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It's probably more slight, probably.
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Something like this,
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but it's going to be a little bit to the right.
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Similarly, two S two is going to be a little bit
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to the right,
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and then two P six is going to be a little bit
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to the right,
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and once again, I'm not drawing it completely perfectly
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'cause I don't have the exact data here.
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Three S two
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would be a little bit to the right.
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Once again,
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only 19 protons versus 20 for calcium,
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so we're pulling a little bit less inwards,
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so we have a lower binding energy
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for any given shell or sub shell,
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and three P six is going to be a little bit to the right,
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like this,
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and then what is the four S sub shell going to look like?
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Well, it doesn't have two electrons in the four S sub shell.
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It only has one,
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'cause it only has 19 electrons and not 20.
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And so it's going to be a little bit to the right.
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It has a lower binding energy
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and it's only going to be half as high
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because you only have one electron, not two.
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So it's going to look something like that.
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That would be the photoelectron spectrum
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of potassium, roughly speaking.
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Now we've already talked about that your outermost shell
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shows where your valence electrons are.
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So if we're thinking about potassium,
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it would be right over there.
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Now that also tells us,
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when we're thinking about the binding energy over here,
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so this binding energy,
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that tells us how much energy do we need
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to remove an electron?
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And so when you're removing that first electron,
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that's your first ionization energy.
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Once you remove that first electron,
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because of all of the interactions between the electrons,
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your photoelectron spectrum would change
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so you can't think about your second
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or third ionization energies,
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but your first ionization energy,
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you just have to think about it's the binding energy
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of your outermost electrons.