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  • - [David] Let's say that we have a line,

  • drawing it right over there,

  • and our goal is to construct another line

  • that is parallel to this line

  • that goes through this point.

  • How would we do that?

  • Well, the way that we can approach it is

  • by creating what will eventually be a transversal

  • between the two parallel lines.

  • So let me draw that.

  • So I'm just drawing a line that goes through my point

  • and intersects my original line.

  • Do that, so it's going to look like that.

  • And then, I'm really just going to use the idea

  • of corresponding angled congruents for parallel lines.

  • So what I can do is now take my compass

  • and think about this angle right over here.

  • So I'll draw it like that.

  • And say, all right, if I draw an arc

  • of the same radius over here,

  • can I reconstruct that angle?

  • And so where should the point be on this left end?

  • Well, to do that, I can just measure

  • the distance between these two points

  • using my compass, so I'm adjusting it a little bit

  • to get the distance between those two points.

  • And then I can use that up over here to figure out,

  • I got a little bit shaky.

  • I can figure out that point right over there.

  • And just like that, I now have two corresponding angles

  • to find my transversal and parallel lines,

  • so what I can do is take my straightedge

  • and make it go through those points that I just created,

  • so let's see, make sure I'm going through,

  • and it would look like that,

  • and I have just constructed two parallel lines.

  • And once again, how do I know that this line

  • is parallel to this line?

  • Because we have a transversal that intersects both of them

  • and these two angles, which are corresponding angles,

  • are congruent.

  • So these two lines must be parallel.

- [David] Let's say that we have a line,

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B1 中級

幾何学的構造:平行線 (Geometric constructions: parallel line)

  • 6 0
    林宜悉 に公開 2021 年 01 月 14 日
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