Placeholder Image

字幕表 動画を再生する

  • We are talking about frieze patterns.

  • So a frieze pattern is a table of numbers. The rule of the game is we start with a row of 1s.

  • Then we'll have more interesting rows, but eventually we want to end up with a row of 1s again.

  • So I will do that.

  • Okay, so there is one parameter in what we are doing:

  • the number of rows, 1, 2, 3, 4, here.

  • So there are, say, 4 rows.

  • And now I will put some numbers in the first row, and I will start, fill out this table.

  • There is only one rule. The rule is that whenever you see a small diamond like this,

  • the product of these two numbers minus the product of these two numbers must be always 1.

  • WE-NS is always 1. That's the rule.

  • Okay, what I'll do, I'll put some "random" numbers. Of course, they are not random,

  • but at this point you are not supposed to understand what they are.

  • In the first row, and actually the row is infinite,

  • so I put the seven numbers and then I repeat them. So, it's 7-periodic.

  • Okay, so it's, should do 1,3, and so on. So now we are in business.

  • Using this diamond rule, we can start to fill out this table. I will do it myself, but, Brady please watch me.

  • Let's see what should be here. The number here times 1 should be 1 less than this product,

  • so 3 minus 1, this should be 2. Let's see. 1 times 3 minus 1 times 2 is 1.

  • Brady: Perfect. Sergei: Next one. Here, 6 minus 1, 5, this should be 5.

  • 3 times 2, 6. 1 times 5, 5. 6 minus 5, 1. Correct?

  • Okay, here. 2 times 2, 4. I put 3 here. Checking: 2 times 2, 4, minus 1 times 3, 3, 4 minus 3, 1.

  • Brady: Okay. Sergei: Okay, here, 1. 2 minus 1.

  • Here, 3. 4 minus 3.

  • Here, well this is a big one, 7. 4 times 2, 8, minus 7, 1.

  • Here, 2, 1, 1, 1.

  • 1, 2, 3, 4, 5, 6, 7.

  • This will also repeat because of the first row repeats with period 7, so the next one should be 2.

  • Brady: So, so far It's been good. We got nice, we got integers, no fractions, nothing complicated.

  • Sergei: Yes. I want to point out that a small miracle has already happened.

  • So if look at this rule, this compass rule,

  • If you know three of these numbers, you can always solve for the remaining one.

  • For example, suppose you know W, E, and N, and you want to solve for S.

  • So what is S? S is WE-1 over N. We subtract, and we divide.

  • So there is no chance, in general, that will stay within positive integers.

  • We divide, so in principle, these should be fractions.

  • Yeah. What we should expect in general if we put rational numbers in the first row,

  • Everything inside should be rational. But I put positive integers and so far it's stable in the positive integers.

  • That's already strange.

  • Alright. So let's do hard work. What should we put here. 10 minus 1 divided by 3, 3. 10 minus 9.

  • What should we put here, 15 minus 1 over 2. 7.

  • Here, 3 minus 1. That's 1. Here, 2.

  • Here, 21 minus 1 over 4. 5.

  • 7 minus 1, 6 over 2. 3.

  • Here, 1. 1, 2, 3, 4, 5, 6, 7. It should be periodic, so the next one must be 3.

  • Brady: The miracle continues! Sergei: The miracle continues, you are right.

  • And, you want the surprise that it will continue to the end.

  • So two more miracles we expect. We expect positive integers in this row, and we expect this one to satisfy the compass rule.

  • Okay, so let me do it a little faster.

  • That will be 4. That will be 2. That will be 1. That will be 3.

  • 2, I guess?

  • 2 and 1. And it should be periodic so the previous one just like this one.

  • And finally, I hope, it all works. 4 minus 3, 1, 8 minus 7, 1,

  • 1, 1, 1, 1, 1, 1. Yes.

  • Brady: So, you filled the sandwich perfectly and you only used integers.

  • Sergei: Right, so you start to wonder what's going on. Brady: Did you choose magic numbers at the start?

  • Well, certainly, certainly the numbers were not random. If you change anything at all randomly, it will break completely.

  • The secret has a name. It's a theorem.

  • It's due to two famous mathematicians, one of them unfortunately not with us, another alive.

  • Coxeter and Conway. John Conway, who is a character in your movies.

  • John: "I'm not gonna worry anymore, ever again."

  • John: I was going to study whatever I thought was interesting.

  • So the theorem explains this phenomenon, and actually gives a complete description, complete classification,

  • of frieze patterns which consist of positive integers.

  • So again, I remind everyone that there is a parameter here, the number of non-trivial rows.

  • Here, this number is 4, but in principle, can be handwritten in anything else.

  • So the theorem is not one theorem, but infinitely many theorems, one for each parameter.

  • To explain what's going on, I need to draw a polygon which will have seven sides.

  • I will partition this heptagon into triangles. I will triangulate it by its diagonals.

  • I will draw this diagonal,

  • and this diagonal,

  • and maybe this one,

  • and possibly this one.

  • Okay, so now we have five triangles which make this heptagon,

  • and I will write numbers at every vertex, and the number is the number of adjacent triangles.

  • So, for example, this vertex has exactly one triangle adjacent to it, so I write 1 here.

  • This vertex has four triangles, so that is 4.

  • This one has 2. 1, 3, 2, and 2. Okay, now we have seven numbers.

  • If you examine this first non-trivial row, you will recognize these numbers starting with this 1, I guess.

  • 1, 3, 2, 2, 1, 4, 2.

  • And then we repeat it. Okay? Brady: So this shape gave you your numbers?

  • Sergei: Yes, exactly.

  • And the brilliant, beautiful theorem of Coxeter and Conway says that this miracle will happen every time.

  • Given an n-gon, we triangulate by diagonals any way we want,

  • it's an interesting question how many ways, I will say something about that,

  • and we put the numbers of triangles adjacent to every vertex around the polygon.

  • And now we create the first seed row, which will be n-periodic. Here it was, n was seven.

  • And we put these numbers in the row, with period n, and then we start to fill out our table using the compass rule.

  • So the claim is that after n minus 3 non-trivial rows, which all consist of positive integers,

  • we will again have a row of 1s. Brady: So that's when you get back to the 1s.

  • Sergei: Exactly. Brady: n minus 3.

  • Sergei: n minus 3. Yes.

  • So that's the way to construct a frieze pattern consisting of positive integers of width n minus 3,

  • and the theorem is that they all are obtained this way, so it's a one-to-one correspondence.

  • If we start with the square this gives us period 4 in the horizontal direction and width 1.

  • Pentagon gives us a 5-periodic pattern with width 2.

  • Hexagon, 6-periodic, width 3.

  • Hep-heptagon you already saw, but you can go to higher, well probably there is not enough room for, here,

  • But it works for every n. Maybe we should start with a square.

  • There are exactly two ways to triangulate it by diagonals. This is one way, and this is another way,

  • and although one is obtained from another by rotation, we consider them as different,

  • so there should be two different frieze patterns of period 4 and width 1.

  • According to these numbers, which are 1, 2, 1, 2, and 2, 1, 2, 1.

  • Not very interesting, but it works. Reality check.

  • Pentagon has five different triangulations by diagonals.

  • They all look the same because the numbers which we write form the same sequence, 3, 1, 2, 2, 1,

  • but again, we consider these triangulations as different, so there are 5 ways to do it.

  • So, 2 ways here, 5 ways here, maybe for complete record we should put triangle which has only 1 triangulation,

  • which you don't need to do, it's already there, and the numbers of course are 1, 1, 1.

  • Hexagon. Hexagon really takes some work. So, this is one.

  • This is a different kind of pattern. I guess there is one other pattern, like so.

  • Brady: That's gonna start giving us quite different numbers isn't it? Sergei: That is correct.

  • If you are willing to believe me, the number will be 14 here, and actually, this sequence, 1, 2, 5, 14,

  • this is a famous sequence, which you can find everywhere. These are Catalan numbers,

  • and they are all over mathematics, all over combinatorics.

  • There are many, many, many interpretations, This is just one of the most common ones.

  • Sure, the next one I guess is 42. Brady: And this is a heptagon.

  • Sergei: This should be heptagon. Yes, indeed.

  • Brady: So does that mean as our polygons get bigger, they'll give us different families of our frieze seeding numbers?

  • Sergei: That is correct. Yes. The first row will depend on n as an n-gon, so it will be n periodic,

  • and on the triangulation. Different triangulations give us different seed rows.

  • Brady: So I want to make a 4-rowed sandwich here, Sergei: Ok.

  • Brady: one of these 4 row sandwiches, obviously I have to use a heptagon, Sergei: Correct.

  • Brady: but I will have different ways to seed that depending on how I triangulated my heptagon. Sergei: Exactly right. Exactly right.

  • So in this example, we chose one particular triangulation, but, for example, you can choose one of the diagonals,

  • let's say this one, erase it, and replace, for example by this one, and that would be a different frieze pattern,

  • different triangulation, the numbers will change as well.

  • Brady: This will always work, no- for every triangulation it will always give me frieze numbers that will...

  • Sergei: This will always works, work, and this is the only thing which will work.

  • So the theorem is that if you want a frieze pattern consisting of positive integers, you should do this, and they all will be obtained this way.

  • Brady: So there's no chance that I could devise a sequence that won't come from a triangulation.

  • Sergei: Absolutely not. Absolutely not. You don't want to see the proof, but it's a theorem,

  • so it has a proof, it's 100% certain, yes. Brady: But it's a, this is... amazing.

  • Sergei: It's amazing. But you, it takes two geniuses, you know. Coxeter and Conway.

  • It's not just any random pair of mathematicians. Yeah, it's really beautiful.

  • Maybe I should say a few words about the place the subject occupies in contemporary mathematics.

  • So, when Coxeter and Conway came up with their result, and when Conway introduced frieze patterns,

  • it seemed like a marginal subject in some sense.

  • I mean there are many beautiful things in mathematics which do not belong to mainstream.

  • Fortunately for the subject, fortunately for all us, now it's really mainstream.

  • So there is a new, relatively new, a theory called the theory of cluster algebras, and this is about 20 years old,

  • and these frieze patterns occupy a very honorable position in this theory, it's one of the main examples,

  • so they're very much studied nowadays, and they are very popular.

  • If you google the subject you will see many, many scientific papers on this subject.

  • So, the intuition of Coxeter and Conway proved itself excellent. They recognized the beauty and now it's important, too.

  • Brady: To see even more from this interview, including the famed lightning bolt in frieze patterns,

  • have a look at our extra footage channel, Numberphile2. There'll be a link on the screen and in the description.

  • This video was filmed at the Mathematical Sciences Research Institute, or MSRI.

  • If you'd like to find out more about MSRI, have a listen to our podcast episode with the director of the institute, David Eisenbud.

  • Again, links are on the screen and down in the description.

We are talking about frieze patterns.

字幕と単語

ワンタップで英和辞典検索 単語をクリックすると、意味が表示されます

B1 中級

フリーズパターン - Numberphile (Frieze Patterns - Numberphile)

  • 3 0
    林宜悉 に公開 2021 年 01 月 14 日
動画の中の単語