Placeholder Image

字幕表 動画を再生する

  • Okay.

  • This lecture is mostly about the idea of similar matrixes.

  • I'm going to tell you what that word similar means

  • and in what way two matrixes are called similar.

  • But before I do that, I have a little more

  • to say about positive definite matrixes.

  • You can tell this is a subject I think is really important and I

  • told you what positive definite meant --

  • it means that this --

  • this expression, this quadratic form, x transpose I

  • x is always positive.

  • But the direct way to test it was with eigenvalues

  • or pivots or determinants.

  • So I -- we know what it means, we know how to test it,

  • but I didn't really say where positive definite matrixes come

  • from.

  • And so one thing I want to say is that they come from least

  • squares in -- and all sorts of physical problems start with

  • a rectangular matrix -- well, you remember in least squares

  • the crucial combination was A transpose A.

  • So I want to show that that's a positive definite matrix.

  • Can -- so I --

  • I'm going to speak a little more about positive definite

  • matrixes, just recapping --

  • so let me ask a question.

  • It may be on the homework.

  • Suppose a matrix A is positive definite.

  • I mean by that it's all --

  • I'm assuming it's symmetric.

  • That's always built into the definition.

  • So we have a symmetric positive definite matrix.

  • What about its inverse?

  • Is the inverse of a symmetric positive definite matrix also

  • symmetric positive definite?

  • So you quickly think, okay, what do I

  • know about the pivots of the inverse matrix?

  • Not much.

  • What do I know about the eigenvalues

  • of the inverse matrix?

  • Everything, right?

  • The eigenvalues of the inverse are

  • one over the eigenvalues of the matrix.

  • So if my matrix starts out positive definite,

  • then right away I know that its inverse is positive definite,

  • because those positive eigenvalues --

  • then one over the eigenvalue is also positive.

  • What if I know that A -- a matrix A and a matrix B are

  • both positive definite?

  • But let me ask you this.

  • Suppose if A and B are positive definite, what about --

  • what about A plus B?

  • In some way, you hope that that would be true.

  • It's -- positive definite for a matrix is kind of like positive

  • for a real number.

  • But we don't know the eigenvalues of A plus B.

  • We don't know the pivots of A plus B.

  • So we just, like, have to go down this list of, all right,

  • which approach to positive definite

  • can we get a handle on?

  • And this is a good one.

  • This is a good one.

  • Can we -- how would we decide that --

  • if A was like this and if B was like this,

  • then we would look at x transpose A plus B x.

  • I'm sure this is in the homework.

  • Now -- so we have x transpose A x bigger than zero,

  • x transpose B x positive for all -- for all x,

  • so now I ask you about this

  • guy.

  • And of course, you just add that and that

  • and we get what we want.

  • If A and B are positive definites, so is A plus B.

  • So that's what I've shown.

  • So is A plus B.

  • Just -- be sort of ready for all the approaches through

  • eigenvalues and through this expression.

  • And now, finally, one more thought about positive definite

  • is this combination that came up in least squares.

  • Can I do that?

  • So now -- now suppose A is rectangular, m by n.

  • I -- so I'm sorry that I've used the same letter A

  • for the positive definite matrixes in the eigenvalue

  • chapter that I used way back in earlier chapters when

  • the matrix was rectangular.

  • Now, that matrix -- a rectangular matrix,

  • no way its positive definite.

  • It's not symmetric.

  • It's not even square in general.

  • But you remember that the key for these rectangular ones

  • was A transpose A.

  • That's square.

  • That's symmetric.

  • Those are things we knew --

  • we knew back when we met this thing

  • in the least square stuff, in the projection stuff.

  • But now we know something more --

  • we can ask a more important question, a deeper question --

  • is it positive definite?

  • And we sort of hope so.

  • Like, we -- we might --

  • in analogy with numbers, this is like --

  • sort of like the square of a number, and that's positive.

  • So now I want to ask the matrix question.

  • Is A transpose A positive definite?

  • Okay, now it's -- so again, it's a rectangular A that

  • I'm starting with, but it's the combination A transpose A

  • that's the square, symmetric and hopefully positive definite

  • matrix.

  • So how -- how do I see that it is positive definite,

  • or at least positive semi-definite?

  • You'll see that.

  • Well, I don't know the eigenvalues of this product.

  • I don't want to work with the pivots.

  • The right thing -- the right quantity to look at is this,

  • x transpose Ax --

  • A -- x transpose times my matrix times x.

  • I'd like to see that this thing --

  • that that expression is always positive.

  • I'm not doing it with numbers, I'm doing it with symbols.

  • Do you see -- how do I see that that expression comes out

  • positive?

  • I'm taking a rectangular matrix A and an A transpose --

  • that gives me something square symmetric,

  • but now I want to see that if I multiply --

  • that if I do this --

  • I form this quadratic expression that I

  • get this positive thing that goes upwards when I graph it.

  • How do I see that that's positive,

  • or absolutely it isn't negative anyway?

  • We'll have to, like, spend a minute on the question

  • could it be zero, but it can't be negative.

  • Why can this never be negative?

  • The argument is --

  • like the one key idea in so many steps in linear algebra --

  • put those parentheses in a good way.

  • Put the parentheses around Ax and what's the first part?

  • What's this x transpose A transpose?

  • That is Ax transpose.

  • So what do we have?

  • We have the length squared of Ax.

  • We have -- that's the column vector Ax that's the row vector

  • Ax, its length squared, certainly greater than

  • or possibly equal to zero.

  • So we have to deal with this little possibility.

  • Could it be equal?

  • Well, when could the length squared be zero?

  • Only if the vector is zero, right?

  • That's the only vector that has length squared zero.

  • So we have -- we would like to --

  • I would like to get that possibility out of there.

  • So I want to have Ax never -- never be zero,

  • except of course for the zero vector.

  • How do I assure that Ax is never zero?

  • The -- in other words, how do I show that there's no null space

  • of A?

  • The rank should be --

  • so now remember -- what's the rank when there's no null

  • space?

  • By no null space, you know what I mean.

  • Only the zero vector in the null space.

  • So if I have a -- if I have an 11 by 5 matrix --

  • so it's got 11 rows, 5 columns, when is there no null space?

  • So the columns should be independent -- what's the rank?

  • n 5 -- rank n.

  • Independent columns, when -- so if I --

  • then I conclude yes, positive definite.

  • And this was the assumption -- then A transpose A is

  • invertible --

  • the least squares equations all work fine.

  • And more than that -- the matrix is even positive definite.

  • And I just to say one comment about numerical things,

  • with a positive definite matrix, you never

  • have to do row exchanges.

  • You never run into unsuitably small numbers or zeroes

  • in the pivot position.

  • They're the right -- they're the great matrixes to compute with,

  • and they're the great matrixes to study.

  • So that's -- I wanted to take this first ten minutes of grab

  • the first ten minutes away from similar matrixes and continue

  • a -- this much more with positive definite.

  • I'm really at this point, now, coming close

  • to the end of the heart of linear algebra.

  • The positive definiteness brought everything together.

  • Similar matrixes, which is coming the rest of this hour

  • is a key topic, and please come on Monday.

  • Monday is about what's called the SVD, singular values.

  • It's the -- has become a central fact in --

  • a central part of linear algebra.

  • I mean, you can come after Monday also, but --

  • Monday is, -- that singular value thing has made it

  • into this course.

  • Ten years ago, five years ago it wasn't in the course,

  • now it has to be.

  • Okay.

  • So can I begin today's lecture proper with this idea

  • of similar matrixes.

  • This is what similar matrixes mean.

  • So here -- let's start again.

  • I'll write it again.

  • So A and B are similar.

  • A and B are -- now I'm -- these matrixes --

  • I'm no longer talking about symmetric matrixes, in --

  • at least no longer expecting symmetric matrixes.

  • I'm talking about two square matrixes n by n.

  • A and B, they're n by n matrixes.

  • And I'm introducing this word similar.

  • So I'm going to say what does it mean?

  • It means that they're connected in the way --

  • well, in the way I've written here, so let me rewrite it.

  • That means that for some matrix M, which has to be invertible,

  • because you'll see that --

  • this one matrix is --

  • take the other matrix, multiply on the right

  • by M and on the left by M inverse.

  • So the question is, why that combination?

  • But part of the answer you know already.

  • You remember -- we've done this -- we've taken a matrix A --

  • so let's do an example of similar.

  • Suppose A -- the matrix A -- suppose it has a full set

  • of eigenvectors.

  • They go in this eigenvector matrix S.

  • Then what was the main point of the whole --

  • the main calculation of the whole chapter was -- is --

  • use that eigenvector matrix S and its inverse

  • comes over there to produce the nicest possible matrix lambda.

  • Nicest possible because it's diagonal.

  • So in our new language, this is saying A is similar to lambda.

  • A is similar to lambda, because there is a matrix,

  • and this particular --

  • there is an M and this particular M

  • is this important guy, this eigenvector matrix.

  • But if I take a different matrix M and I look at M inverse A M,

  • the result won't come out diagonal,

  • but it will come out a matrix B that's similar to A.

  • Do you see that I'm -- what I'm doing is, like --

  • I'm putting these matrixes into families.

  • All the matrixes in one -- in the family are similar to each

  • other.

  • They're all -- each one in this family is connected to each

  • other one by some matrix M and the --

  • like the outstanding member of the family is the diagonal guy.

  • I mean, that's the simplest, neatest matrix

  • in this family of all the matrixes that are similar to A,

  • the best one is lambda.

  • But there are lots of others, because I can take different --

  • instead of S, I can take any old matrix M,

  • any old invertible matrix and -- and do it.

  • I'd better do an example.

  • Okay.

  • Suppose I take A as the matrix two one one two.

  • Okay.

  • Do you know the eigenvalue matrix for that?

  • The eigenvalues of that matrix are --

  • well, three and one.

  • So that -- and the eigenvectors would be easy to find.

  • So this matrix is similar to this one.

  • But my point is --

  • but also, I can also take my matrix, two one one two,

  • I could multiply it by -- let's see, what --

  • I'm just going to cook up a matrix M here.

  • I'm -- I'll -- let me just invent -- one four one zero.

  • And over here I'll put M inverse,

  • and because I happened to make that triangular,

  • I know that its inverse is that, right?

  • So there's M inverse A M, that's going to produce some matrix --

  • oh, well, I've got to do the multiplication,

  • so hang on a second, let --

  • I'll just copy that one minus four zero one

  • and multiply these guys so I'm getting two nine one and six,

  • I think.

  • Can you check it as I go, because you -- see I'm just --

  • so that's two minus four, I'm getting a minus two nine

  • minus 24 is a minus 15, my God, how did I get this?

  • And that's probably one and six.

  • So there's my matrix B.

  • And there's my matrix lambda, there's my matrix A

  • and my point is these are all similar matrixes.

  • They all have something in common,

  • besides being just two by two.

  • They have something in common.

  • And that's -- and what is it?

  • What's the point about two matrixes that are built out

  • of --

  • the B is built out of M inverse A M.

  • What is it that A and B have in common?

  • That's the main -- now I'm telling you the main fact about

  • similar matrixes.

  • They have the same eigenvalues.

  • This is -- this chapter is about eigenvalues,

  • and that's why we're interested in this family of matrixes that

  • have the same eigenvalues.

  • What are the eigenvalues in this example?

  • Lambda.

  • The eigenvalues of that I could compute.

  • The eigenvalues of that I can compute really fast.

  • So the eigenvalues are three and one --

  • for this for sure.

  • Now did we -- do you see why the eigenvalues are three and one

  • for that one?

  • If I tell you the eigenvalues are three and one, you prick --

  • quickly process the trace, which is -- and four --

  • agrees with four and you process the determinant,

  • three times one --

  • the determinant is three and you say yes, it's right.

  • Now I'm hoping that the eigenvalues of this thing

  • are three and one.

  • May I process the trace and the determinant for that one?

  • What's the trace here?

  • The trace of this matrix is four minus two and six,

  • and that's what it should be.

  • What's the determinant minus twelve plus fifteen is three.

  • The determinant is three.

  • The eigenvalues of that matrix are also three and one.

  • And you see I created this matrix just like --

  • I just took any M, like, one that popped into my head

  • and computed M inverse A M, got that matrix,

  • it didn't look anything special but it's --

  • like A itself, it has those eigenvalues three and one.

  • So that's the main fact and let me write it down.

  • Similar matrixes have the same eigenvalues.

  • So I'll just put that as an important point.

  • And think why.

  • Why is that?

  • So that's what that family of matrixes is.

  • The matrixes that are similar to this A

  • here are all the matrixes with eigenvalues three and one.

  • Every matrix with eigenvalues three and one,

  • there's some M that connects this guy

  • to the one you think of.

  • And then of course, the most special guy in the whole family

  • is the diagonal one with eigenvalues three and one

  • sitting there on the diagonal.

  • But also, I could find --

  • I mean, tell me just a couple more members of the family.

  • Another -- tell me another matrix that has eigenvalues

  • three and one.

  • Well, let's see, I -- oh, I'll just make it triangular.

  • That's in the family.

  • There is some M that -- that connects to this one.

  • And -- and also this.

  • There's some matrix M -- so that M inverse A M comes out to be

  • that.

  • There's a whole family here.

  • And they all share the same eigenvalues.

  • So why is that?

  • Okay.

  • I'm going to start -- the only possibility is to start with Ax

  • equal lambda x.

  • Okay, so suppose A has the eigenvalue lambda.

  • Now I want to get B into the picture here somehow.

  • You remember B is M inverse A M.

  • Let's just remember that over here.

  • B is M inverse A M.

  • And I want to see its eigenvalues.

  • How I going to get M inverse A M into this equation?

  • Let me just sort of do it.

  • I'll put an M times an M inverse in there, right?

  • That was --

  • I haven't changed the left-hand side,

  • so I better not change the right-hand side.

  • So everybody's okay so far, I just put in there -- see,

  • I want to get a -- so now I'll multiply on the left by M

  • inverse --

  • I have to do the same to this side

  • and that number lambda's just a number,

  • so it factors out in the front.

  • So what I have here is this was safe.

  • I did the same thing to both sides.

  • And now I've got B.

  • There's B.

  • That's B times this vector M inverse

  • x is equal to lambda times this vector M inverse x.

  • So what have I learned?

  • I've learned that B times some vector

  • is lambda times that vector.

  • I've learned that lambda is an eigenvalue of B also.

  • So this is -- if -- so this is --

  • if lambda's an eigenvalue of A, then I can write it this way

  • and I discover that lambda's an eigenvalue of B.

  • That's the end of the proof.

  • The eigenvector didn't stay the same.

  • Of course I don't expect the eigenvectors to stay the same.

  • If all the eigenvalues are the same and all the eigenvectors

  • are the same, then probably the matrix is the same.

  • Here the eigenvector changes, so the eigenvector --

  • so the point is then the eigenvector of B --

  • of B is M inverse times the eigenvector of A.

  • Okay.

  • That's all that this says here.

  • The eigenvector of A was X, and so the M inverse --

  • similar matrixes, then have the same eigenvalues

  • and their eigenvectors are just moved around.

  • Of course, that's what we -- that's what happened way back

  • --

  • and the most important similar matrixes are to diagonalize.

  • So what was the point when we diagonalized?

  • The eigenvalues stayed the same, of course.

  • Three and one.

  • What about the eigenvectors?

  • The eigenvectors were whatever they were for the matrix A,

  • but then what were the eigenvectors

  • for the diagonal matrix?

  • They're just -- what are the eigenvectors of a diagonal

  • matrix?

  • They're just one zero and zero one.

  • So this step made the eigenvectors nice,

  • didn't change the eigenvalues, and every time we

  • don't change the eigenvalues.

  • Same eigenvalues.

  • Okay.

  • Now -- so I've got all these matrixes in --

  • I've got this family of matrixes with eigenvalues three and one.

  • Fine.

  • That's a nice family.

  • It's nice because those two eigenvalues are different.

  • I now have to --

  • to get into that --

  • the -- into the less happy possibility that the two

  • eigenvalues could be the

  • same.

  • And then it's a little trickier, because you remember

  • when two eigenvalues are the same,

  • what's the bad possibility?

  • That there might not be enough --

  • a full set of eigenvectors and we might not be able

  • to diagonalize.

  • So I need to discuss the bad case.

  • So the bad -- can I just say bad?

  • If lambda one equals lambda two, then the matrix

  • might not be diagonalizable.

  • Suppose lambda one equals lambda two equals four,

  • say.

  • Now if I look at the family of matrixes with eigenvalues four

  • and four, well, one possibility occurs to me.

  • One family with eigenvalues four and four has this matrix in it,

  • four times the identity.

  • Then another -- but now I want to ask also about the matrix

  • four four one zero.

  • And my point -- here's the whole point of this --

  • of this bad stuff, is that this guy is not in the same family

  • with that one.

  • The family of a -- of matrixes that have eigenvalues four

  • and four is two families.

  • There's this total loner here who's in a family off --

  • right?

  • Just by himself.

  • And all the others are in with this guy.

  • So the big family includes this one.

  • And it includes a whole lot of other matrixes, all --

  • in fact, in this two by two case, it -- you see where --

  • what do I mean -- so what I using, this word family --

  • in a family, I mean they're similar.

  • So my point is that the only matrix that's similar to this

  • is itself.

  • The only matrix that's similar to four times the identity

  • is four times the identity.

  • It's off by itself.

  • Why is that?

  • The -- if this is my matrix, four times the identity,

  • and I take it, I multiply on the right by any matrix M,

  • I multiply on the left by M inverse, what do I get?

  • This is any M, but what's the result?

  • Well, factoring out a four, that's

  • just the identity matrix in there.

  • So then the M inverse cancels the M,

  • so I've just got this matrix back again.

  • So whatever the M is, I'm not getting

  • any more members of the family.

  • So this is one small family, because it only has one person.

  • One matrix, excuse me.

  • I think of these matrixes as people by this point,

  • in eighteen oh six.

  • Okay, the other family includes all the rest --

  • all other matrixes that have eigenvalues four and four.

  • This is somehow the best one in that family.

  • See, I can't make it diagonal.

  • If I -- if it's diagonal, it's this one.

  • It's in its own, by itself.

  • So I have to think, okay, what's the nearest I

  • can get to diagonal?

  • But it will not be diagonalizable.

  • That -- do you know that that matrix is not diagonalizable?

  • Of course, because if it was diagonalizable,

  • it would be similar to that, which it isn't.

  • The eigenvalues of this are four and four,

  • but what's the catch with that matrix?

  • It's only got one eigenvector.

  • That's a non-diagonalizable matrix.

  • Only one eigenvector.

  • And somehow, if I made that one into a ten or to a million,

  • I could find an M, it's in the family, it's similar.

  • But the best -- so the best guy in this family is this one.

  • And this is called the Jordan --

  • so this guy Jordan picked out -- so he, like, studied,

  • these families of matrixes, and each family,

  • he picked out the nicest, most diagonal one.

  • But not completely diagonal, because there's nobody --

  • there isn't a diagonal matrix in this family,

  • so there's a one up there in the Jordan form.

  • Okay.

  • I think we've got to see some more matrixes in that family.

  • So, all right, let me -- let's just think of some other

  • matrixes whose eigenvalues are four and four but they're not

  • four times the identity.

  • So -- and I believe that --

  • that this -- that all the examples we pick up will be

  • similar to each other and -- do you see why --

  • in this topic of similar matrixes,

  • the climax is the Jordan form.

  • So it says that every matrix --

  • I'll write down what the Jordan form -- what Jordan discovered.

  • He found the best looking matrix in each family.

  • And that's -- then we've got -- then we've covered all matrixes

  • including the non-diagonalizable one.

  • That -- that's the point, that in some way,

  • Jordan completed the diagonalization by coming

  • as near as he could, which is his Jordan form.

  • And therefore, if you want to cover all matrixes,

  • you've got to get him in the picture.

  • It used to be -- when I took eighteen oh six,

  • that was the climax of the course, this Jordan form stuff.

  • I think it's not the climax of linear algebra anymore,

  • because --

  • it's not easy to find this Jordan form

  • for a general matrix, because it depends on these eigenvalues

  • being exactly the same.

  • You'd have to know exactly the eigenvalues and it --

  • and you'd have to know exactly the rank and the slightest

  • change in numbers will change those eigenvalues,

  • change the rank and therefore the whole thing is numerically

  • not an -- a good thing.

  • But for algebra, it's the right thing

  • to understand this family.

  • So just tell me another matrix -- a few more matrixes --

  • so more members of the family.

  • Let me put down again what the best one is.

  • Okay.

  • All right.

  • Some more matrixes.

  • Let's see, what I looking for?

  • I'm looking for matrixes whose trace is what?

  • So if I'm looking for more matrixes in the family,

  • they'll all have the same eigenvalues, four and four.

  • So their trace will be eight.

  • So why don't I just take, like, five and three --

  • I've got the trace right, now the determinant should be what?

  • Sixteen.

  • So I just fix this up -- shall I put maybe a one and a minus one

  • there?

  • Okay.

  • There's a matrix with eigenvalues four and four,

  • because the trace is eight and the determinant is sixteen.

  • And I don't think it's diagonalizable.

  • Do you know why it's not diagonalizable?

  • Because if it was diagonalizable,

  • the diagonal form would have to be this.

  • But I can't get to that form, because whatever

  • I do with any M inverse and M I stay with that form.

  • I could never get -- connect those.

  • So I can put down more members -- here --

  • here's another easy one.

  • I could put the four and the four and a seventeen

  • down there.

  • All these matrixes are similar.

  • If I'm -- I could find an M that would show that that one is

  • similar to that one.

  • And in -- you can see the general picture is I can take

  • any a and any 8-a here and any -- oh, I don't know,

  • whatever you put it'd be -- anyway, you can see.

  • I can fill this in, fill this in to make the trace equal eight,

  • the determinant equal 16, I get all that family of matrixes

  • and they're all similar.

  • So we see what eigenvalues do.

  • They're all similar and they all have only one eigenvector.

  • So I -- if I'm -- if you were going to --

  • allow me to add to this picture, they have the same lambdas

  • and they also have the same number of independent

  • eigenvectors.

  • Because if I get an eigenvector for x I get one for -- for A,

  • I get one for B also.

  • So -- and same number of eigenvectors.

  • But even more than that --

  • even more than that --

  • I mean, it's not enough just to count eigenvectors.

  • Yes, let me give you an example why it's not even

  • enough to count eigenvectors.

  • So another example.

  • So here are some matrixes --

  • oh, let me make them four by four --

  • okay, here -- here's a matrix.

  • I mean, like if you want nightmares,

  • think about matrixes like these.

  • Uh, so a one off the diagonal -- say a one there, how many --

  • what are the eigenvalues of that matrix?

  • Oh, I mean --

  • okay.

  • What are the eigenvalues of that matrix?

  • Please.

  • Four 0s, right?

  • So we're really getting bad matrixes now.

  • So I mean, this is, like --

  • Jordan was a good guy, but he had to think about matrixes

  • that all -- that had, like -- an eigenvalue repeated four times.

  • How many eigenvectors does that matrix have?

  • Well, I'm -- eigenvectors will be --

  • since the eigenvalue is zero, eigenvectors will be

  • in the null space, right?

  • I'm -- eigenvectors have got to be A x equal zero x.

  • So what's the dimension of the null space?

  • Two.

  • Somebody said two.

  • And that's right.

  • How -- why?

  • Because you ask what's the rank of that matrix,

  • the rank is obviously two.

  • The number of independent rows is two,

  • the number of independent columns is two,

  • the rank is two so the null -- the dimension of the null space

  • is four minus two, so it's got two eigenvectors.

  • Two eigenvectors.

  • Two independent eigenvectors.

  • All right.

  • The dimension of the null space is two.

  • Now, suppose I change this zero to a seven.

  • The eigenvalues are all still zero, how -- what about --

  • how many eigenvectors?

  • What's the dimension of the -- what's the rank of this matrix

  • now?

  • Still two, right?

  • So it's okay.

  • And actually, this would be similar to the one that

  • had a zero in there.

  • But it's not as beautiful, Jordan picked this one.

  • He picked -- he put ones --

  • we have a one on the -- above the diagonal for every missing

  • eigenvector, and here we're missing two because we've got

  • two, so we've got two eigenvectors and two are

  • missing, because it's a four by four matrix.

  • Okay, now -- but I was going to give you this second example.

  • 0 1 0 0, let me just move the one.

  • Oop, not there.

  • Off the diagonal and zero zero zero zero zero.

  • Okay.

  • So now tell me about this matrix.

  • Its eigenvalues are four zeroes again.

  • Its rank is two again.

  • So it has two eigenvectors and two missing.

  • But the darn thing is not similar to that one.

  • A -- a count of eigenvectors looks like these could be

  • similar, but they're not.

  • Jordan -- see, this is like -- a little three by three block

  • and a little one by one block.

  • And this one is like a two by two block and a two

  • by two block, and those blocks are called Jordan blocks.

  • So let me say what is a Jordan block?

  • J block number I has --

  • so a Jordan block has a repeated eigenvalue, lambda I, lambda I

  • on the diagonal.

  • Zeroes below and ones above.

  • So there's a block with this guy repeated,

  • but it only has one eigenvector.

  • So a Jordan block has one eigenvector only.

  • This one has one eigenvector, this block has one eigenvector

  • and we get two.

  • This block has one eigenvector and that block has

  • one eigenvector and we get two.

  • So -- but the blocks are different sizes.

  • And that -- it turns out Jordan worked out --

  • then this is not similar, not similar to this one.

  • So the -- so I'm, like, giving you the whole story --

  • well, not the whole story, but the main themes of the story --

  • is here's Jordan's theorem.

  • Every square matrix A is similar to A Jordan matrix J.

  • And what's a Jordan matrix J?

  • It's a matrix with these blocks, block --

  • Jordan block number one, Jordan block number two and so on.

  • And let's say Jordan block number d.

  • And those Jordan blocks look like that,

  • so the eigenvalues are sitting on the diagonal,

  • but we've got some of these ones above the diagonal.

  • We've got the number of --

  • so the number of blocks --

  • the number of blocks is the number of eigenvectors,

  • because we get one eigenvector per block.

  • So what I'm -- so if I summarize Jordan's idea --

  • start with any A.

  • If its eigenvalues are distinct, then what's it similar

  • to?

  • This is the good case.

  • if I start with a matrix A and it has different eigenvalues --

  • it's n eigenvalues, none of them are repeated,

  • then that's a diagonal -- diagonalizable matrix --

  • the Jordan blocks is -- has -- the Jordan matrix is diagonal.

  • It's lambda.

  • So the good case --

  • the good case, J is lambda.

  • All -- there are --

  • d=n.

  • There are n eigenvectors, n blocks, diagonal, everything

  • great.

  • But Jordan covered all cases by including

  • these cases of repeated eigenvalues and missing

  • eigenvectors.

  • Okay.

  • That's a description of Jordan.

  • That -- that's --

  • I haven't told you how to compute this thing,

  • and it isn't easy.

  • Whereas the good case is the -- the good case is what 18.06 is

  • about.

  • The -- this case is what 18.06 was about 20 years ago.

  • So you can see you probably won't have on the final exam

  • the computation of a Jordan matrix for some horrible thing

  • with four repeated eigenvalues.

  • I'm not that crazy about the Jordan form.

  • But I'm very positive about positive definite matrixes

  • and about the idea that's coming Monday,

  • the singular value decomposition.

  • So I'll see you on Monday, and have a great weekend.

  • Bye.

Okay.

字幕と単語

ワンタップで英和辞典検索 単語をクリックすると、意味が表示されます

B1 中級

28.類似行列とヨルダン式 (28. Similar Matrices and Jordan Form)

  • 2 0
    林宜悉 に公開 2021 年 01 月 14 日
動画の中の単語