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  • [inaudible] -- topic. I've been talking --

  • I've been multiplying matrices already, but certainly time for me

  • to discuss the rules for matrix multiplication.

  • And the interesting part is the many ways you can do it,

  • and they all give the same answer. So it's -- and they're

  • all important. So matrix multiplication,

  • and then, come inverses. So we're --

  • we -- mentioned the inverse of a matrix, but there's --

  • that's a big deal. Lots to do about inverses

  • and how to find them. Okay, so I'll begin with how to

  • multiply two matrices. First way,

  • okay, so suppose I have a matrix A multiplying a matrix B and --

  • giving me a result -- well, I could call it C.

  • A times B. Okay. So, l- let me just review the

  • rule for w- for this entry. That's the entry in

  • row I and column J. So that's the I J entry.

  • Right there is C I J. We always write the row number and

  • then the column number. So I might --

  • I might -- maybe I take it C three four, just to make it specific.

  • So instead of I J, let me use numbers. C three four.

  • So where does that come from, the three four entry?

  • It comes from row three, here, row three and column four,

  • as you know. Column four.

  • And can I just write down, or can we write down the formula for

  • it? C three four is --

  • if we look at the whole row and the whole

  • column, the quick way for me to say it is row three of A --

  • I could use a dot for dot product. I won't often use that,

  • actually. S- dot column four of B.

  • And -- but this gives us a chance to just, like, use a little

  • matrix notation. What are the entries?

  • What's this first entry in row three?

  • The first -- the first -- that number that's

  • sitting right there is A,

  • so it's got two indices and what are they? [Class response,

  • inaudible] Three one. So there's an A three one there.

  • Now what's the first guy at the top of column four? [Class

  • response, inaudible] So what's sitting up there?

  • [Class response, inaudible] B one four, right.

  • So that this dot product starts with A three one times B one four.

  • And then what's the next -- so this is like I-

  • I'm accumulating this sum, then comes the next guy, A three two,

  • second column, times B two four, second row.

  • So it's B A three two, B two four and so on.

  • Just practice with indices. Oh, let -- let me even practice with

  • a summation formula. So this is --

  • I -- I -- most of the course, I use whole vectors.

  • I very seldom, get down to the details of these

  • particular entries, but here we'd better do it.

  • So I'm -- it's some kind of a sright?

  • Of things in row three, column K shall I say?

  • Times things in row K, column four. Do you see that that's what's --

  • that's what we're seeing here? This is K is one,

  • here K is two, on along -- so up --

  • so the sum goes all the way along the row and down the column,

  • say, one to N. So that's what the A --

  • the C three four entry looks like. A sum of A three K B K four.

  • Just takes a little practice to do that.

  • Okay. And, uh -- oh, well,

  • maybe I should say -- when are we allowed to multiply

  • these matrices? What are the shapes of these things?

  • The shapes are, uh -- if we allow them to be not

  • necessarily square matrices. If they're square,

  • they've got to be the same size. If they're rectangular, they're

  • not the same size. If they're rectangular,

  • this might be -- well, I always think of A as M by N.

  • M rows, N columns. So that sum goes to N.

  • Now what's the point -- how many rows does B have to have?

  • [Class response, inaudible] N. N.

  • The number of rows in B, the number of guys that we meet

  • coming down has to match the number of ones across.

  • So B will have to be N by something. Whatever. P.

  • So then -- the number of columns here has to match the number of rows

  • there, and then what's the result? What's the shape of the result?

  • What's the shape of C, the output? Well, it's got these same M rows,

  • or -- it's got M rows. And how many columns?

  • [Class response, inaudible] P. M by P. Okay.

  • So there are M times P little numbers in there,

  • entries, and each one, looks like that.

  • Okay. So that's the standard rule. That's the way people think of

  • multiplying matrices. I do it too.

  • But that's -- that's -- I want to talk about other

  • ways to look at that same calculation,

  • looking at whole columns and whole rows.

  • Okay. So can I do A B C again? A B equaling C again?

  • But now, tell me s- tell me about, yeah.

  • Let me -- I'll put it up here. So here goes A, again,

  • times B producing C. And again,

  • this is M by N. This is N by P and this is M by P.

  • Okay. Now I want to look

  • at whole columns. I want to look at the columns of --

  • here -- in fact - here's the second way to multiply matrices.

  • Because I'm going to build on what I know already.

  • How do I multiply a matrix by a column?

  • How do I -- I know how to multiply this matrix

  • by that column. Th- th- shall I call

  • that column one? That tells me column

  • one of the answer. The matrix times the first column is

  • that first column. Because none of this stuff entered

  • that part of the answer. The matrix times the second column

  • is the second column of the answer. Do you see what I'm saying?

  • That I could think of multiplying a matrix by a vector,

  • which I already knew how to do, and I can think of

  • the vec- I can think of just P columns sitting side by side,

  • just like resting next to each other.

  • And I multiply A times each one of those.

  • And I get the P columns of the answer.

  • Do you see this as -- this is quite nice, to be able to

  • think, okay, matrix multiplication works so

  • that I can just think of having several columns,

  • multiplying by A and getting the columns of the answer.

  • So, like, here's column one -- a -- shall I call that --

  • here's a -- shall I call that column one?

  • And what's going in there is A times column one.

  • Okay. So that's the picture a column at a time.

  • So what does that tell me? What does that tell me

  • about these columns? These columns of C are combinations,

  • because we've seen that before, of columns of A.

  • Every one of these comes from A times this,

  • and A times a vector is a combination of the columns of A.

  • And -- right -- and it makes sense,

  • because the columns of A have length M and the columns of

  • C have length M. And every column of C is a --

  • is some combination of the columns of A.

  • And it's these numbers in here that tell me what combination it is.

  • Do you see that? That out --

  • that in that answer, C, I'm seeing stuff that's col-

  • that's combinations of these columns.

  • Now, suppose I look at it -- that's two ways now.

  • The third way is look at it by rows. So now let me change to rows. Okay.

  • So now I can think of a row of A -- a row of A multiplying all these

  • rows here and producing a row of the product.

  • So this row takes a combination of these rows and that's the answer.

  • So these rows of C are combinations of what?

  • Of -- tell me how to finish that. The rows of C,

  • when I have a matrix B, it's got it's rows and I multiply by

  • A, and what does that do? It mixes the rows up.

  • It makes -- it creates combinations of the rows

  • of -- [student response, inaudible] -- B, thanks.

  • Rows of B. That's what I wanted to see,

  • that this -- that this answer -- I can see where the pieces are

  • coming from. The rows in the answer are coming as

  • combinations of these rows. The columns in the answer are com-

  • coming as combinations of those columns.

  • And now that's -- so that's three ways.

  • Now you can say, okay, what's the fourth way?

  • The fourth way -- so that's -- now we've got,

  • like, the regular way, the column way, the row way and -- what's left?

  • The -- the one that I can -- I -- I want to tell you about --

  • well, one way is columns times rows. What happens if I multiply --

  • so th- this was row times column, it gave a number.

  • Okay. Now I want to ask you about column times row.

  • What does -- if I multiply a column of A times a

  • row of B, what shape am I ending up with?

  • So if I take a column times a row, that's definitely different from

  • taking a row times a column. So a column of A was --

  • what -- what's the shape of a column of A?

  • N by one. A column of A is a column.

  • It's got M entries and one column. And what's a row of B?

  • It's got one row and P columns. So what's the shape --

  • what do I get if I multiply a column by a row?

  • I get a big matrix. I get a full-sized matrix.

  • If I multiply a column by a row, I get -- should we just do one?

  • Let me take the column two three four times the row one six.

  • That is a -- that product there -- I mean, when I'm just following the

  • rules of matrix multiplication,

  • those rules are just looking like -- kind of

  • petite, kind of small, because the -- the rows here are so

  • short and the columns there are so short, but they're the same

  • length, one entry. So what's the answer?

  • What's the answer if I do two three four times one six,

  • just for practice? Well, what's the first row of the

  • answer? Two twelve. And the second row of the answer is

  • three eighteen. And the third row of the answer is

  • four twenty four. Actually, what am I --

  • I mean, that's a very special matrix, there.

  • Very special matrix. What can you tell me about its

  • columns, the columns of that matrix?

  • They're multiples of this guy, right?

  • They're multiples of that one. Which follows our rule.

  • We said that the columns of the answer were combinations,

  • but there's only -- to take a combination of one guy,

  • it's just a multiple. The rows of the answer,

  • what can you tell me about those three rows?

  • They're all multiples of this row. They're all multiples of

  • one six, as we expected. But I'm getting a full-sized

  • matrix. And now, just to complete this

  • thought, if I have,-- now, l- let me right

  • down the fourth way. A B is a sum of columns

  • of A times rows of B. So that, for example, if my --

  • if my matrix was two three four and then had another column,

  • say, seven eight nine, and my matrix here has --

  • say, started with one six and then had another column like zero zero,

  • then -- h- here's the fourth way, okay?

  • I've got two columns there, I've got two rows there.

  • So the beautiful rule is -- see, the whole thing by columns

  • and rows is that I can take the first column times the first

  • row and add the second column times the second row.

  • So that's the fourth way, that -- that I can take columns times rows,

  • first column times first row, second column times second row and add.

  • Actually, what will I get? What will the answer be for that

  • matrix multiplication? Well, this one it's just going to

  • give us zero, so in fact I'm back to this --

  • that's the answer, for that matrix multiplication. [sneeze]

  • Uh -- I'm -- I'm sort of,

  • like, happy to put up here these facts about matrix multiplication,

  • because it gives me a chance to write down special

  • matrices like this. This is a special matrix.

  • All those rows lie on the same line.

  • All those rows lie on the line through one six.

  • If I draw a picture of all these row vectors, they're all

  • the same direction. If I draw a picture of these two

  • column vectors, they're in the same direction.

  • Later, I would use this language. Not too much later, either.

  • I would say the row space, which is like all the combinations

  • of the rows, is just a line for this matrix.

  • The row space is the line through the vector one six.

  • All the rows lie on that line. And the column space is also a line.

  • All the columns lie on the line through the vector two three four.

  • So this is like a really minimal matrix.

  • And it's because of these ones. Okay. So that's a third way.

  • Now, even -- yeI -- can I --

  • will you -- would you take -- this is -- I- I want to say one more

  • thing about matrix multiplication while we're on the subject.

  • And it's this. You could also multiply --

  • you could also cut the matrix into blocks and do the multiplication

  • by blocks. Yethat's actually so,

  • useful that I want to mention it. Block multiplication.

  • So I could take my matrix A and I could

  • chop it up, like, maybe just for simplicity,

  • let me chop it into two -- into four square blocks.

  • Suppose it's square. Let's just take a nice case.

  • And B, suppose it's square also, same size.

  • So these sizes don't have to be the same.

  • What they have to do is match properly.

  • Here they certainly will match. So here's the rule for

  • block multiplication, that if this has blocks like,

  • A -- so maybe A one, A two, A three, A four

  • are the blocks here, and these blocks are B one,

  • B two, B three and B four? Then the answer I can find block --

  • I can find that block. And if you tell me what's in that

  • block, then I'm going to be quiet about matrix multiplication for the

  • rest of the day. What goes into that block?

  • You see, these might be -- this matrix might be --

  • these matrices might be, like, twenty by twenty with blocks that

  • are ten by ten, to take the easy case where all the

  • blocks are the same shape. And the point is that I could

  • multiply those by blocks. And what goes in here? What's that?

  • What's that -- what's that block in the answer?

  • A one B one, that's a matrix times a matrix,

  • it's the right size, ten by ten. An- any more?

  • Plus, what's the -- what else goes in there?

  • Student: A two -- A two B three, right?

  • It's just like block rows times block columns.

  • A- I- I don't -- nobody, I think,

  • not even Gauss could see instantly that it works.

  • But somehow, if we check it through,

  • all five ways we're doing the same multiplications.

  • So this -- this familiar multiplication is what we're really

  • doing when we do it by columns, by rows by columns times rows and by

  • blocks. Okay. I just have to,

  • like, get the rules straight for matrix multiplication.

  • Okay. All right,

  • I'm ready for the second topic, which is inverses.

  • Okay. Ready for inverses. And let me do it for square

  • matrices first. Okay. So I've got

  • a square matrix A. And w- and it may or may not have an

  • inverse, right? Not all matrices have inverses.

  • In fact, I -- that's the most important question

  • you can ask about the matrix,

  • is if it's sq- if you know it's square,

  • is it invertible or not? If it is invertible,

  • then -- then there is some other matrix, shall I call it A inverse?

  • And what's the -- what's -- if A inverse exists --

  • so this is if -- there's a big if here.

  • If this matrix exists, and a -- and it'll be really central

  • to figure out when does it exist? And then if it does exist,

  • how would you find it? But -- what's the --

  • what's the equation here that I haven't -- that I have

  • to finish now? This matrix,

  • if it exists multiplies I and produces --

  • Student: I. I, thanks. The identity.

  • And, actually, there's a little more to it.

  • Because normally -- I mean, that -- right now,

  • that's like a left inverse. It's sitting on the left of A.

  • But a real -- a- an inverse for a square matrix

  • could be on the right as well --

  • so it -- so,-- this is true, too,

  • that it's -- if I have a --

  • yein fact, this is not -- this is probably the --

  • this is something that's not easy to prove, but it works.

  • That a left -- that for a -- square matrices,

  • a left inverse is also a right inverse.

  • If I can find a matrix on the left that gets the identity,

  • then also that matrix on the right will produce that identity.

  • For rectangular matrices, we'll see a left inverse that isn't

  • a right inverse. In fact, the shapes

  • wouldn't allow it. But for square matrices,

  • the shapes allow it and it happens, if A has an inverse.

  • Okay, so give me some cases -- let's see.

  • I -- I hate to be negative here, but let's talk about the case with

  • no inverse. So -- so this is --

  • these matrices are called invertible or non-singular -- those

  • are the good ones. And we want to be able to identify --

  • w- how -- if we're given a matrix, has it got an inverse?

  • Can I talk about the singular case? No inverse. All right.

  • Best to start with an example. Tell me an example --

  • let -- let's get an example up here. Let's make it two by two --

  • of a matrix that has not got an inverse.

  • And let's see why. Let me - let me write one up.

  • No inverse. Let's -- let's see why.

  • Let me write up -- one three two six.

  • Why does that matrix have no inverse? [Clears throat]

  • You can -- you could answer that various ways.

  • Give me one reason. Well, you could -- if you

  • know about determinants, which you're not supposed to

  • [laughter], you could take its determinant

  • and you would get -- Zero. Okay. Now -- all right.

  • Let me -- let me ask you other reasons.

  • I mean, as for other reasons that that matrix isn't invertible.

  • H- here, I could use -- use what I'm saying here.

  • Suppose -- suppose A times other matrix gave the identity.

  • Wh- why is that not possible? Because -- oh,

  • yetell -- I'm thinking about columns here.

  • If I multiply this matrix A by some other matrix, then the --

  • the result -- what can you tell me about the

  • columns? They're all multiples of

  • those columns, right? If I multiply A by another

  • matrix that -- the product has columns that come

  • from those columns. So can I get the identity

  • matrix? No way. The columns of the identity matrix,

  • like one zero -- it's not a combination of those

  • columns, because those two columns lie on the -- both

  • lie on the same line. Every combination is just going to

  • be on that line and I can't get one zero.

  • So, do you see -- do you see that --

  • that sort of column picture of the matrix not being invertible.

  • In fact, here's another reason. I- this is even a more

  • important reason. Well, how can I say more important?

  • All those are important. This is another way to see it.

  • A matrix has no inverse -- yeah -- h- here -- now this is

  • important. A matrix has no --

  • a square matrix won't have an inverse if

  • there's -- if -- i- no inverse because I can solve --

  • I can find an X of -- a vector X with A times --

  • this A times X giving zero. That -- this is the

  • reason I like best. That matrix won't have an inverse.

  • Can you -- well, let me change I to U.

  • So tell me a vector X that, solves A X equals zero.

  • I mean, this is, like, the key equation.

  • In mathematics, all the key equations have zero on

  • the right-hand side. So what's the X?

  • T- tell me an X here -- so now I'm going to put --

  • slip in the X that you tell me and

  • I'm going to get zero. What -- what X would do that job?

  • [Student response, inaudible] Three of negative one?

  • Is that the one you picked, or -- yeah.

  • Or another -- well, if you picked zero with zero,

  • I'm not so excited, right? Because that would always work.

  • So it's -- so it's o- it's really the fact that this vector isn't zero

  • that's important. It's a non-zero vector and three

  • negative one would do it. That just says three of this column

  • minus one of that column is the zero column.

  • Okay. So now I know that A couldn't be invertible.

  • But what's the reasoning? If -- if A X is zero,

  • suppose I multiplied by A inverse.

  • Yeor -- I -- w- well here's the reason.

  • Here -- here -- this is why this spells disaster for

  • an inverse. The matrix can't have an inverse if

  • some combination of the columns gives z- it gives nothing.

  • Because, I could take A X equals zero, I could multiply by A inverse

  • and what would I discover? Suppose I take that equation

  • and I multiply by -- i- i- if A inverse existed,

  • which of course I'm going to come to the conclusion it can't

  • because if it existed, if there was an A inverse

  • to this dopey matrix, I would multiply that equation by

  • that inverse and I would discover X is zero.

  • If I multiply A by A inverse on the left, I get X.

  • If I multiply by A inverse on the right, I get zero.

  • So I would discover X was zero. But it -- X is not zero.

  • X -- this guy wasn't zero. There it is.

  • It's three minus one. So, conclusion --

  • only, it -- take us some time to really work

  • with that conclusion -- are conclusion will be the --

  • that in- that -- that non-invertible matrices,

  • singular matrices, some combinations of th-

  • some combinations of their columns gives the zero column.

  • It -- th- they they take some vector X into zero.

  • A- and there's no way A inverse can recover, right?

  • That's what this equation says. This equation says I take this

  • vector X and multiplying by A gives zero.

  • But then when I multiply by A inverse, I can never

  • escape from zero. So there couldn't be an A inverse.

  • Where here -- okay, now fix -- all right.

  • Now let -- let me take a -- let -- all right, back to the

  • positive side. Let's take a matrix that

  • does have an inverse. And why not invert it? Okay.

  • Can I -- so let me take on this third board a matrix --

  • shall I fix that up a little? Tell me a matrix that

  • has got an inverse. Well, let me say one three two --

  • what shall I put there? [Student response, inaudible]

  • Well, don't put six, I guess is -- right?

  • Do I -- any -- any favorites here?

  • [Student response, inaudible] One? Or eight? I don't

  • care. What, seven? Seven. Okay. Seven

  • is a lucky number. All right,

  • seven, okay. Okay. So -- now what's our idea?

  • We believe that this matrix is invertible.

  • Th- those who like determinants have quickly taken its determinant and

  • found it wasn't zero. Those who like columns,

  • and probably that -- that department

  • is not totally popular yet -- but those who like columns will

  • look at those two columns and say, hey, they point in different

  • directions. So I can get anything.

  • Now, let -- let me see, what do I mean?

  • How am I going to computer A inverse?

  • So A inverse -- here's A inverse,

  • now, and I have to find it. And -- and what do I get when I'm --

  • when I do this multiplication? The identity.

  • I -- you know, forgive me for taking two by twos,

  • but -- l- it's good to keep the computations manageable and let the

  • ideas come out. Okay, now what's the idea I want?

  • I'm -- I'm looking for this matrix A inverse,

  • how am I going to find it? Right now,

  • it's,-- I've got four numbers to find.

  • I'm going to look at the first column.

  • W- let me take this first column, A B.

  • What's up there? Wh- what equa- tell me this.

  • What equation does the first column satisfy?

  • The first column satisfies A times that column is one zero.

  • The first column of the answer. Y- and the second column,

  • C D, satisfies A times that second column is zero one.

  • You see that finding the inverse is like solving two systems.

  • One system, when the right-hand side is one zero

  • -- I- I'm just going to split it into two pieces.

  • That -- that -- I don't -- I'm --

  • I don't even need to rewrite it. I can -- I can s- take A times --

  • so let me put it here. A times column J of A inverse is

  • column J of the identity. I've got N equations.

  • I've g- I've got, well, two in this case.

  • And they have the same matrix, A, but they have different

  • right-hand sides. The right-hand sides are just the

  • columns of the identity, this guy and this guy.

  • And these are the two solutions. Do you see what I'm going --

  • I'm looking at that equation by columns.

  • I'm looking at A times this column, giving that guy, and A times that

  • column giving that guy. So -- Essentially --

  • so this is like the Gauss -- we're back to Gauss.

  • We're back to solving systems of equations,

  • but we're solving -- we've got two right-hand sides

  • instead of one. That's where Jordan comes in.

  • So -- so at the very beginning of the lecture,

  • I mentioned Gauss Jordan, let me write it up again.

  • Okay. Here's the Gauss Jordan idea. Gauss Jordan is --

  • solves -- solve two equations at once.

  • Okay. Let me show you how the -- how the mechanics go.

  • H-h-how do I solve a -- a single equation?

  • So the two equations are one three two seven, multiplying

  • A B gives one zero. And the other equation is the same

  • one three two seven multiplying C D gives zero one.

  • Okay. That'll tell me the two columns of the inverse.

  • I'll have inverse. In other words,

  • if I can solve with this matrix A, if I can solve with that right-hand

  • side and that right-hand side, I'm invertible.

  • I've got it. Okay. And the -- and Jordan sort of said

  • to Gauss, solve them together, look at the matrix --

  • if we just solve this one, I would look at one three two seven,

  • and how do I deal with the right-hand side?

  • I stick it on as an extra column, right?

  • He -- you remember that's -- that's this augmented matrix.

  • That's the matrix when I'm watching the right-hand side at the same time,

  • doing the same thing to the right side that I do to the left?

  • So I just carry it along as an extra column.

  • Now I'm going to carry along two extra columns.

  • And I'm going to do whatever Gauss wants, right?

  • I'm going to do elimination. I'm going to get this to be simple

  • and this thing will turn into the inverse.

  • This is what's coming. I'm going to do elimination steps to

  • make this into the identity, and lo and behold,

  • the inverse will show up here. K--- let's do it. Okay.

  • So what are the elimination steps? So you see --

  • here's my matrix A and here's the identity, like, stuck

  • on, augmented on. Student: I'm sorry, u- --

  • Yeah? Student: --

  • is the two and the three supposed to be switched?

  • Did I -- oh, no, they weren't supposed to be

  • switched. Sorry. Thanks. Okay. Thank you very much.

  • And there -- I've got them right.

  • Okay, thanks. Okay. So let's do elimination.

  • All right, it's going to be simple, right?

  • So I take two of this row away from this row.

  • So this row stays the same and two of those come away from this.

  • That leaves me with a zero and a one and two of these away

  • from this -- is that what that --

  • is that what you're getting -- after one elimination

  • step, I- I'll -- let me sort of separate the --

  • the left half from the right half. So two of that first row got

  • subtracted from the second row. Now -- now this is an upper

  • triangular form. Gauss would quit, but Jordan

  • says keeps going. Use elimination upwards.

  • Subtract a multiple of equation two from equation one to -- to

  • get rid of the three. So let's go the whole way.

  • So now I'm going to -- this guy is fine, but I'm going to --

  • what do I do now? What's my final step that

  • produces the inverse? I multiply this by the right number

  • to get up to there -- to -- to remove that three.

  • So I guess, I -- since this is a one,

  • there's the pivot sitting there. I multiply it by three and subtract

  • from that, so what do I get? I'll have one zero --

  • oh, yethat was my whole point. I'll multiply this by three and

  • subtract from that, which will give me seven.

  • And I multiply this by three and subtract from that, which

  • gives me a minus three. And what's my hope, belief?

  • Here -- here I started with -- with A and the identity, and I ended

  • up with the identity and who? [Student response, inaudible]

  • That better be A inverse. That's the Gauss Jordan idea.

  • Start with this long matrix, double-length A I, eliminate,

  • eliminate until this part is down to I, then this one will --

  • must be for some reason, and we've got to find the reason --

  • must be A inverse. Shall I just check that it works?

  • Let me just check that -- can I multiply this matrix --

  • this -- this part times A, I'll carry A over here and just do

  • that multiplication. I -- you'll see I'll do it

  • the old fashioned way. Seven minus six is a one.

  • Twenty one minus twenty one is a zero, minus two plus two is a zero,

  • minus six plus seven is a one. Check. So that is the inverse.

  • That's the Gauss Jordan idea. So, you'll --

  • one of the homework problems or more than one for Wednesday will ask you

  • to go through those steps. I think you just got to go through

  • Gauss Jordan a couple of times [cough] but I --

  • so I -- like, yei- just to see the mechanics.

  • But the, um, important thing is,

  • why -- w- is, like, what happened? Why did we -- why did we

  • get A inverse there? Let me ask you that.

  • W- we got -- so we take --

  • we do row reduction, we do elimination on this long

  • matrix A I until the first half is up.

  • Then a second half is A inverse. Well, h- how do I see that?

  • Let me put up here how I see that. So here's my --

  • here's my Gauss Jordan thing, and I'm doing stuff to it.

  • So I'm -- well, whole lot of Es. Remember those are those

  • elimination matrices. Those are the --

  • those are the things that we figured out last time.

  • Yes, that's what an elimination step is -- is --

  • is -- it's -- in matrix form,

  • I'm multiplying by some Es. And the result --

  • well, so I'm multiplying by a whole bunch of Es.

  • So, I get a -- I- can I call the overall matrix E?

  • That's the elimination matrix, the product of all those little

  • pieces. What do I mean by little pieces?

  • Well, there was an elimination matrix that subtracted two

  • of that away from that. Then there was an elimination matrix

  • that subtracted three of that away from that.

  • I -- I guess in this case, that was all.

  • So there were just two Es in this case, one that did this step

  • and one that did this step and together they gave me an

  • E that does both steps. And the net result was

  • to get an I here. And you can tell me what

  • that has to be. This is, like,

  • the -- th- the picture of what happened.

  • If E multiplied A, whatever that E is --

  • we never fer- figured it out in -- in -- b- -- by

  • -- b- in this way. But whatever that E times e- e- that

  • er- E is, E times A is -- What's E times A?

  • [Student response, inaudible]. It's I.

  • That E, whatever the heck it was, multiplied A and produced I.

  • So E must be -- E A equaling I tells us what E is,

  • namely it is -- Student: It's the inverse of A.

  • It's the inverse of A. Great. And therefore,

  • when the second half, when E multiplies I, it's E --

  • [inaudible] inverse. You see the picture

  • looking that way? E times A is the identity.

  • It tells us what E has to be. It has to be the inverse,

  • and therefore, on the right-hand side,

  • where E -- where we just smartly tucked on the identity,

  • it's turning in, step by step -- it's turning into A

  • inverse. There is the --

  • the statement of Gauss Jordan elimination.

  • That's how you find the inverse. Where -- we look --

  • we can look at it as elimination, as solving N equations at the same

  • time and tacking on N columns, solving those equations and up goes

  • the N columns [inaudible]. Okay, thanks.

  • See you on Wednesday. [Class noise]

[inaudible] -- topic. I've been talking --

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Lec 3|MIT 18.06 線形代数 2005年春学期 (Lec 3 | MIT 18.06 Linear Algebra, Spring 2005)

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    Autumn Pak Long に公開 2021 年 01 月 14 日
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