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"Today is going to be another, sort of, special topic. It's actually really important [inaudible].
One of my favorite things because it is so useful. We're going to be talking about using
nuclear overhauser effect in structured stereochemistry determination, and I'll try to show you why
I think this is so useful with some examples, maybe related things to the exam.
So in terms of what the nuclear overhauser effect is; I've been talking about this in
C13 NMR but not why this is useful. So the nuclear overhauser effect, or NOE,
is a change in intensity of the resonance of a proton or another nucleus, I'll put this
in terms of protons but I'm really talking about any type of nucleus, in response to
or upon irradiation of a nearby proton. And, so what do I mean; so let's say from
the point of view of a molecule I mean that you have two protons, of course it could be
a proton and a C13 in a molecule like so, where they're near to each other in space,
not necessarily in connectivity, that are just a few angstrom apart in space.
And, we're going to do something that specifically irradiates one proton and obviously what you
are doing is not a spatial resolution but rather frequency resolution; in other words
each protons appears at a different frequency and so you're going to hit one of these specifically
at this frequency and what that does here is it responds -- now, when you're irradiating
what you're doing is equalizing the population of alpha and beta states. And, when you do
that, that in turn alters the equilibrium population of alpha and beta states of other
nuclei that are nearby. And the way it does this is it opens new relaxation pathways.
And since it is a relaxation process, it doesn't occur instantly. It takes time on the order
of relaxation time; in other words, hundreds of milliseconds, typically, to build up.
And so, what you see, well, you see in your C NMR -- there are two reasons in the C NMR
that your C-H peaks, and C-H2 peaks, are bigger than your [inaudible]: one of these reasons
is the nuclear overhauser effect, carbon that has hydrogens attached to it is nearby to
a hydrogen, so when you irradiate the hydrogens you actually affect the population of alpha
and beta states in the carbon; another reason is that relaxation, because your pulsing reasonably
fast and [inaudible] usually relax slowly you end up with lower intensity but one of
the reasons is the NOE. Ok, so what does that mean for that hypothetical
cartoon of a molecule where you have Ha and Hb that are next to each other in space? It
means that if you have a spectrum that looks like this where you have Ha and Hb, if I irradiate
Ha, now the spectrum changes and we don't see Ha anymore and the peak for Hb gets a
little bit bigger. Now, these effects are pretty small in proton
NMR. The theoretical maximum H-H NOE is only 50%. And normally you see values that are
a lot smaller than that, you might see typically 10%. So what I've drawn here is a cartoon
where Hb is appreciably bigger, is actually not recall the case, its just going to be
just a teeny tiny bit bigger. Now, I said there's this effect that affects
carbon and because of the difference in magnetogyric ratio with proton and carbon you actually
have a bigger effect. So with H1 to C13 NOE here the affect is actually
200%. So there you can have a peak get substantially bigger.
Now, NOEs involve relaxation, this in turn involves motion of molecules so like tumbling
motion which means the NOW is sensitive to the size of the molecule and how fast it tumbles
because that is going to affect different types of relaxation in molecules. So high
molecular weight molecules, so we're talking typically over 2000, but these numbers aren't
carved in stone, but let's say greater than 2000 or if you slow down the tumbling by a
viscous solvent, then your NOE is actually negative and the theoretical maximum is -100%
for H-H NOE. And this is important in protein structure
determination rather than in small molecule chemistry, which is where we focus. Now these
days, if you look at some of the natural products tat are getting published in the Journal of
Organic Chemistry or Journal of natural Products or JACS, some of these small molecules are
pretty hair molecules; in other words, hey are small molecules but they are big small
molecules. And that big small molecule regime is actually a pain in the neck, because what
happens as you go from small molecules that have positive NOE to big molecules that have
a negative NOE is what?" "No NOE?"
"No NOE. So the medium-sized molecules often end up have 0 NOE. And I really don't want
to be putting hard numbers on this because it depends on what solvent you're using, it
depends on the field strength of the spectrometer, it depends on the shape of the molecule, it
depends on the temperature, but I'm going to step out on a limb here and say molecular
weight range of say 1000-1500, which is a big small molecule, is often 0 NOE. Or close
to 0. And there is a related technique called a
rotating overhauser effect that's often used to bring out those NOE in that intermediate
range. Alright, I want to show you an example of a traditional NOE experiment; and I'll
show you an old example and then I'll show you an example that is sort of relevant to
organic chemistry research. I just want to show you the general gist of it; it's on the
first page on the handout. Alright, so this is an example in the book by Derome which
is a nice, a nice book, it's actually a precursor to Claridge, which is a book I've given you
some readings from that's sort of a second edition because Derome had passed away. So
here's a molecule, the particular molecule isn't important, buy you'll see the issues.
So this is an H1 NMR spectrum of the molecule and this is an NMR spectrum in which we've
irradiated one of the protons; specifically we irradiated this proton. And, in doing this,
the authors didn't quite equalize the population -- you still see a little bit of the peak.
The peak has gone from this over to the smaller version. And it's hard to tell if anything
has gotten bigger, it looks like that one has gotten bigger. But the way in which one
historically does this, because the spectrum involves such small changes, the way one historically
does this is called a difference NOE spectrum. And, difference NOE spectrum, one is literally
subtracting one spectrum from another spectrum; you're subtracting the unradiated spectrum
from irradiated spectrum so I'll put a minus sign, or actually I guess your technically
subtracting the [inaudible] and going ahead and coordinate transforming. And so I want
to point out the features that we see: so the fist thing we see of course is the now
irradiated peak is negative; after all, if we had something where we've almost equalized
the population or alpha and beta states and we take away something where we have a positive
peak you get a negative peak, but I want to show you the features.
Ok, the thing that's glaring you in the face in this literally textbook example is that
we see a nice NOE over to the peak here. So there's some spatial proximity between this
proton and this proton in the molecule. I want to show you some of the other features
in the spectrum: now, one of the things about the traditional NOE experiment is the conditions
of doing the irradiation, create little perturbations in the spectrum, and actually to do it right
what you do is you do one spectrum where you irradiate here in this case about 1.15 ppm
and this one in order to minimize the subtraction artifacts you actually go ahead and irradiate
somewhere else where nothing is, like over here or over here; but, even with that, there
are some perturbations. So this is what you would call a subtraction artifact. In other
words, it's not an NOE, we don't have a particular peak up or down, what's happened is there's
been an infinitesimally, a teeny tiny shift in the position of this peak because o f the
irradiation which gives us the positive character on one side and the negative character on
the other side. If I were looking at this I'd know just from recognition that there's
no NOE, but another way, a very good way, and something you really should do, is slap
an integral on it; and if you slap an integral on it of course the integral would go up as
the area registered and then go back down, and you'd end up, this would be an integral
here, so you'd end up with no net rise, no net area.
Now, one of the challenges, in any sort of conventional one-dimension NOE experiment
is selectively hitting this peak here. 'Cause you're trying to hit all of the lines here
in this peak, without hitting this peak; when the peaks are maybe 1/10 of a ppm apart, it's
hard to do that. It's easier if you have singlets; I usually tend to go to singlets if I can,
harder if you have multiplets because you have to apply a band of radiation that's wide
enough to hit this, without hitting this. And as you can see, we've got incomplete selectivity
here. So, to put it another way if I was testing a hypothesis that this proton is spatially
close to this one, and I hit this one and I see this one get bigger, but I also hit
this one a teeny tiny bit, there's this worry in the back of my mind: Oh maybe my hypothesis
wasn't being tested completely, because maybe I'm hitting this one as well, and maybe it's
this one enhancing this one. So what kind of experiment could you do to corroborate
this result; what kind of NOE experiment could you do to corroborate the result from this
experiment?" "Could you try to hit the number 1 peak?"
"Beautiful! Exactly! And, so we would try a corroboratory experiment as well
where you irradiate here. And usually NOE experiments usually end up being done in sets.
So you're going to do some 1-D NOE experiments on [inaudible], and this was part of the course
that everyone hated so I've cut it down; I've had you go ahead and hit every peak that could
be hit selectively in [inaudible]. It honestly doesn't take that long, imagine if this were
your thesis molecule it would be no big deal to spend three or four hours on the NMR spectrometer
for an important problem; but, we're 22 people here, you've got other things to do. So I've
cut it down to 1 or 2 nice, 1-D experiments where I basically preselected the key experiment
and we'll also do a [inaudible] experiment. But the 1-D NOE experiment is a beautiful
experiment because you can probe very specific questions.
So this is kind of a textbook example: I want to talk -- I'll give you a real example in
just a second and show you something I think is cool, if I can find my eraser that I've
seem to have misplaced here, but fortunately I have the emergency backup eraser -- anyway,
before I give you a real example and we look a [inaudible] spectra, I just want to show
you one other point of this that actually ties in sort of to thinking about problems
that you might encounter. So I just want to point out one sort f thing here, and that's
a three-spin system. So, sometimes observing an NOE doesn't necessarily mean proximity
and I'll show you an example. So a three-spin system wit h coupling, and again I'll give
you my little [inaudible] cartoon for things. So imagine that Hc is J-coupled with Hb, but
it's not spatially close to Ha, whereas Ha and Hb are close to each other. What can happen
is if I irradiate Ha, of course we'll see a NOE to Hb, in this case a positive NOE.
And remember, this is occurring because by leveling the populations of alpha and beta
states of Ha, I'm setting up new relaxation pathways that are perturbing the alpha and
beta states of Hb. But that perturbation then ends up altering the populations Hc, and in
this particular alignment, we end up with an NOE over here, a negative NOE. So, it's
usually going to be smaller, you usually can tell, but let me give you a real example;
and I think this was taken from the Derome book. So the molecule in this particular case
was a trichloro-toluene derivative, like so, and in this particular real experiment we
have an ortho proton and we have a meta proton. In this particular experiment they irradiated
the chloromethyl group over here and observed a 19.2% NOE over here to the ortho proton
and a -2.6% NOE over here to the meta proton. Now, I guess, looking at this particular molecule
it reminds me of your exam problem [inaudible], so on the first part of your midterm exam
remember the nitro-toluene problem and you were there just using a combination of understanding
coupling patterns and the inductive effect of a nitro group, the electron-withdrawing
effect, the resonance effect of the nitro group and the effect of a methoxy group, most
of you were able to assign your resonances and figure out among the 2,4-disubstituted
isomers and the 2,5-disubstituted isomers. Here, of course, the effects with chlorine
aren't as pronounce, just imagine in our minds eye that you had a molecule and you were trying
to tell whether it was the 2,4 or the 2,5 compound, and of course maybe in this particular
case, you wouldn't have as clear a differentiation in chemical shift, but if you look at this
here you can imagine, if we irradiated in this case you would see an enhancement in
this ortho proton here which would be a doublet with only meta coupling, a tight doublet;
if you irradiated over here in this molecule, you would see the ortho proton enhanced which
would be a doublet with ortho coupling. So in other words, even if the spectra of these
two molecules, the 2,4 and 2,5 isomers, were very similar in chemical shift, you would
be able to tell, from an NOE experiment, which isomer you had by telling whether it was a
doublet of 8 Hz being enhanced or a doublet of 3 Hz being enhanced. So that's an example
immediately that I can hand you of the utility of an NOE experiment. Now, another example
that I can give you, and again I'll harken back to the exam to a problem that I guess
about 2/3 of you did, and that was the beta-lactone problem and there we weren't trying to tell
stereoisomers apart, but imagine for a moment, I'll get [inaudible] the beta-lactone case
as an example. Imagine for a moment we have a beta-lactone and imagine instead of just
having a methyl group at this position, imagine that we had methyl group and an ethyl group
at these two positions, and now we had a methyl group over here of unknown stereochemistry.
You can now imagine that you irradiate this methyl group, this is going to be your methyl
doublet [inaudible], and now you ask is it enhancing the CH2 group of the ethyl group
or is it enhancing the CH3 singlet of the methyl group and you can again address the
question of whether your diastereomer the cis or the trans relationship between the
two methyl groups; in other words, whether we had this diastereomer or this diastereomer."
"And, it would enhance the one that is one the same side as the [inaudible]?"
"Well, it would enhance it more, and you're asking a very, very good question. So, the
question that you're asking is basically: Is the NOE a litmus test? And the answer is
no; this is why comparison is so important. And now I didn't happen to include these in
the handout for the class but I have a very similar example, and I'm going to show you
exactly what it means and then we are going to talk about some distances. And actually,
you know I've been harping on the value of molecular models, molecular models become
really, really, really useful when you want to ask questions about distances.
Alright, so let's take a look at a real example, this is just one that I pulled from my own
experience with the use of NOEs to determine stereochemistry. The example that I'm going
to [inaudible] is actually a cool reaction, it's a named reaction that probably nobody
in this room has heard of, it's the McCoy reaction and if the professor Van Vranken
asks you for a mechanism for it I bet you would all get it. So, the substrate for the
reaction is an alpha-halo carbonyl compound. This happened to be a silo ketone or what's
called an acylsilane and it's a TBDMS [inaudible] but you can also do this for an ester. And
when you take this compound, an alpha-halo carbonyl compound and you treat it with LDA
and then you treat it with and alpha-beta unsaturated carbonyl compound, in this case
I used [inaudible], you get a cyclopropane product, and I'll draw that for you. And the
great thing about reactions invented early on in the century is that every new reaction
that you invent can get you a name [inaudible], so this is the McCoy reaction. Alright, so
the product that we get is a cyclopropane of undetermined stereochemistry, and unfortunately
in this particular example we have a 3:1 mixture of diastereomers. Alright, let me pull down
the screen and give us a chance to take a look at the spectrum of these two diastereomers.
Alright, so we have these two diastereomers and we'll call them isomer B and isomer A.
And, just to get our bearings straight the region around 7ppm is the aromatic region
in each of these. The region over here is the methyl groups on our silicon. Here is
our tert-butyl on the silicone. Here is our isolated methyl group, and these are the ring
protons on the cyclopropane ring. And so on isomer B we see a similar thing, we see our
aromatic resonances, we see our ring CHs, we see our methyl, our tert-butyl, and now
we see our two methyls on silicon. Alright, why do we get two peaks for two methyls on
silicon?" [Inaudible]
"Diastereo-what?" [Inaudible]
"They are diastereotopic! Now, remember I said when you have any sort of stereocenter
in a molecule and now you have a methylene group with two hydrogens on it or a carbon
with two methyls on it, those are diastereotopic. They're topologically different from each
other. In one case, they show up at pretty similar chemical shifts; in other case, which
is interesting, they have a high degree of what we call magnetic [inaudible], in other
words difference in chemical shifts. Now this is an example of where the NOE just shines
as an experiment because we have a testable hypothesis built into the molecule. In the
diastereomer on the left, the methyl group is going to be relatively close to those hydrogens
on the ring; in the diastereomer on the right, the methyl group is relatively far away, and
we're fortunate enough to have both of them. So, let's start with our NOE experiment on
isomer B. So in this particular NOE experiment, we irradiate that methyl group and this is
the difference NOE so this is the spectrum of isomer B, and this is the difference NOE.
And we don't see a heck of a lot, you can see this is an example of a subtraction artifact
here, but you look and you see very, very clearly those two ring protons have nice NOEs.
I want to know how big an NOE: I can slap my ruler on this integral, I've already done
this, this distance here was 74 millimeters, and that's for 3 hydrogens. And over here
I slap my ruler on this integral and it comes out to 2.1 millimeters for one hydrogen and
over her e I slap my ruler on it, it's 2.5 millimeters for one hydrogen. And so if I
take 2.1 divided by 74 divided by 3 I find out its equal to 0.085 or I have an 8.5% NOE
and if I do the same over here I find if I have the value 10% NOE, and so I'm very happy.
I irradiate, I get about an 8-10% NOE, and I say great! We know what a diastereomer means.
Now, you want to be careful; you do this same experiment, and I was fortunate we had both
diastereomers, you do this same experiment here, so this is diastereomer A, and we irradiate,
and we see a teeny tiny enhancement, it's little. A little baby NOE. Over here, and
over here it's about 0.5 millimeters each, and this one on this particular example was
about 73 millimeters for each hydrogen, and it ends up to about 2% NOE. And it's nice
with both diastereomers in hand, we've done a comparison. You irradiate one diastereomer's
methyl group, you get a nice NOE, the other you get a little NOE. The first one is cis,
A is cis, and B is trans. But, imagine, imagine for a moment, that I've
gotten this reaction in the diastereomer [inaudible], and I've only gotten one diastereomer, and
imagine I really, really wanted it, in order to make a natural product, to be the cis diastereomer
and I do it and I say 'Oh yeah, look I got an NOE!' Imagine the trouble [inaudible],
because then I would go on with this and think 'Oh, I have what I want,' and later on I make
my natural product, if I were making a natural product, and I find it doesn't match the published
spectrum, and my thesis would be titled 'Total Synthesis [inaudible],' whatever the natural
product is. [Inaudible]. I would still get a Ph.D. but I wouldn't get a paper in JACS
or something [inaudible]. So you really need to be careful, this was a good example. Now,
if you look in here, there are some teeny tiny hints; so imagine this was the only one
I had, there are some teeny tiny hints that this really is the trans one. And if you look
at the integrals, and I like to slap an integral on everything. Why do I like to slap an integral
on everything? 'Cause it's easy to see. If you have a big peak, if you have a double
that's standing up there nice and tall, it's easy to see it get bigger. But imagine you
had a little peak that's split into a big multiplet that's short, and it gets just a
little bit bigger, you may not see it. So you slap an NOE everywhere, and you say 'Oh,
wait a second, ok I've got some subtraction artifacts here but I see a teeny tiny NOE
here. You can see this guy here has just gotten a teeny tiny bit bigger, I wouldn't stake
my dissertation on it, but if you measure that integral it's about 1.0 millimeter, that
translates to about a 4% NOE, right, because it's 1.0 divided by 73 divided by 3 is equal
to 0.04, 4%. So I look at that, and I say 'Oh wait a second.' So, in other words, if
I only have this diastereomer, I wouldn't want to assign it on the basis of that NOE,
because we are seeing a little NOE between the cis phenyl group and the methyl group
and a little NOE with those trans hydrogens and the methyl group but I'd at least be able
to look at this spectrum and say, 'Wow,' pull myself back, even though I wanted the isomer
in which the methyl group was cis to the hydrogens there was enough data saying it isn't. In
fact, there is a good deal of data saying it's trans to those hydrogens. So, anyway,
be careful with NOEs, usually we're talking about having multiple data sets, multiple
NOEs pointing in a particular direction. Now, this cis-trans business really brings up a
very, very important question, and that question is what is close, and what is not close? How
close is close? Alright, let's talk a little bit about molecular
geometry first, talk about [inaudible]. The Van der Waals radius of hydrogen, anyone know
it off the top of their head?" [Inaudible]
"A few good numbers to keep in your head." [Inaudible]
"Ok, let's take a carbon-carbon bond, what's a carbon-carbon single bond?"
[Inaudible] "One picometers, or... I'm kind of an angstrom
kind of guy. 1.54 angstroms. So the Van der Waals radius is on that same scale, it's 1.1
angstroms. The C-C bonds, the C sp3 sp3 single bond is 1.54 angstroms. Ok, so that's at least
kind of calibrated us. So, what does that mean? That means that if 1.1 angstroms is
the radius, 2.2 angstroms for two hydrogens is going to be touching; so 2.2 angstroms
is close, so that's at least a calibration. Ok, so another thing that's important is how
NOEs vary. NOEs scale as distance to the inverse 6. I always calibrate myself in my mind by
setting up a little table. When we were talking last time about dynamic effects in NMR and
I said, 'Alright, what's 10 kilocalories per mole?' Well 10 kilocalories per mole becomes
slow at negative 50 degrees C. 15, kind of at room temperature, is right about the cross
over; 20 or a hair less than 20 is sort of crossing over [inaudible]. And we can do similar
things here, so let me calibrate myself. So let's take 2.5 angstroms, if I take 1 over
2.5 to the 6, that's equal to 4.1 times 10 to the negative 3. So let's say 2.5 angstroms,
we'll call that close. And if we say the relative NOE, for that, let's call that one. And then
I'm just going to calibrate myself from there. So let me take 3.0 angstroms for comparison
and if I now take 1 over 3.0 to the 6, I get 1.4 times 10 to the negative 3, and so the
relative value is 0.33. And if I do the same for 3.5 angstroms, take 1 over 3.5 to the
6, that gives me 5.4 times 10 to the negative 4. The relative value is 0.13. Ok, what does
that mean? That means, if you imagine 2.5 angstroms and say that's close, that gives
you an NOE of a certain intensity, let's say that intensity was 10%, like we saw in our
cyclopropane. Now imagine we have a distance of 3.0 or 3.5 angstroms, well, I expect to
still see some NOE, but that NOE would be weaker, it would be like 3.3% or 1.3%. This
is exactly what we are seeing in the cyclopropane case. The cis isomer gave us an NOE that was
about 10%. The trans isomer gave us an NOE that was sort of, you know, 2.0%, somewhere
around there. It was detectable but obviously not as strong. the trans isomer gave us an
NOE that was sort of, you know, 2.0%, somewhere around there. It was detectable but obviously
not as strong. Let's call this medium. Let's just continue
our calibration. 4.4 angstroms, 1 over 4 to the 6, is equal to 2.4 times 10 to the negative
4. And now we're at 0.06. Now you might say, well, by the time you're at 4 angstroms, let's
call it 'not so close.' What do I mean? I mean, you might still get a teeny tiny NOE
at 4 angstroms but it's not going to be a really big NOE, but again, I wouldn't stake
a stereochemical determination on seeing that; if I see an NOE between two protons, I say
'Oh they can't be cis, they can't be close, because I see an NOE is very small.' You might
say, 'Wait a second, he just said in class that you could still see something at 3 and
a half or 4 angstroms.' Now I'm going to calibrate us with models in a second which is one of
the reasons as I said earlier, I've been making such a big deal about models. I'll give you
one other number: 1.8 angstroms. 1.8 angstroms is the distance between two hydrogens on a
methylene group; those two hydrogens are jammed in each other and closer than Van der Waals
radius. If I take that, the relative would be 7.2. So what does that mean? That means
if I have two diastereotopic hydrogens in a methylene, and I irradiate one, you may
well see a very, very, very strong NOE. That's like the beta-lactone, when you had the two
diastereotopic hydrogens. If I irradiated one, I could well see a strong NOE. Ok, what's
close ,what's far. I made up these models; I didn't have [inaudible]
at the time, I don't think it had even been invented [inaudible]. Same basic thing [inaudible].
Ok, so I just took a few systems that I use to calibrate my own thinking. We just saw
an example of a cylcopropane with a methyl group on it, and guess what? The hydrogen
on the cyclopropane is pretty darn close to a hydrogen, the methyl group on the cylcopropane
is pretty darn close to a cis hydrogen, 2.4 angstroms, 2.2 angstroms in this particular
model. But at the same time, we see 3.5 angstroms for the trans hydrogen, which is the exactly
the sort of thing we saw on our NOE experiment. Alkenes, alkene stereochemistry, this is great.
you have a methyl group on an alkene and you want to know which hydrogen is cis to it,
which is trans; the cis hydrogen is 2.3 angstroms, clearly close, but the trans isn't infinitely
far away, it's 3.7 angstroms. I did the same with the cyclobutane, cyclopentanes can be
very tricky. You know, NOEs really aren't a litmus test with cyclopentanes; I put a
methyl group on a cyclopentane, and you'll look at the methyl group, and yeah it's close
to the cis hydrogen, it's also close to the trans hydrogen. You're going to be getting
some 5 membered ring compounds and you're going to have to look at multiple NOEs to
see which is close which is far. I will also point out, and you can't see it on this model
but it'll come up later, when you have a cyclopentane and you have two hydrogens in a 1 and 3 positions,
if you see a NOE between them that really can only be cis. You won't be guaranteed to
see it, it'll depend on the pucker of the ring, but you will see it if it's cis. Or
if you see it, it pretty much must be cis. I put an axial methyl on a cyclohexane and
you can see that axial methyl bangs into the hydrogens here very nicely. This is a methoxybenzene
and you can see the ortho relationship as well, so. Alright, I want to finish up with
a couple of additional comments and one last example. So the experiment that is now run
is a PFG-NOE, also called a gNOE, so this is a more modern version of a difference NOE
experiment. It's a NOE experiment that uses pulsed-field gradients. And I can talk more
about that later but right now I'll say it's cleaner than the difference NOE. You'll be
doing this with your [inaudible]. Another experiment is a NOESY, we'll be talking about
it later, but it's a 2-D NOE experiment. We'll be using it later on. I'll give you one example.
Very data rich. And there are NOEs and again we'll be talking more about this later on.
ROESY experiment which is NOE in a rotating frame and that's particularly good for intermediate
sized molecules. Which give near 0 NOEs. Alright, I want to conclude with one class example.
And I'll just show you an example of how beautiful a set of NOEs can be from a NOESY experiment
where you get multiple data that give you confirmation in stereochemistry. So this is
a molecule, a natural product, it's a [inaudible] natural product called Aphanamol. And this
is a NOESY experiment of it. NOESY experiments are 2-D, they give cross peaks, based on spatial
proximity, so they are NOE cross peaks. And if you look at this, of course, what's cool
is we have this 5 membered ring fused to a 7 membered ring. I'll draw it out flat just
so you can see it. And of course you have, you have an alkene here, and of course you
have some stereochemical issues because you have a ring junction in the molecule, and
I'll tell you now that the ring juncture is cis, but of course you'll want to be able
to tell that, because you wouldn't necessarily know that. And there's an isopropyl group,
and the isopropyl group is cis to the hydrogens of the ring junction. So now let's take a
look at the NOEs we see and how they help show the stereochemistry. So, for example,
we see a nice NOE between the hydrogen at 4 and the hydrogen at 11, they are cis to
each other, they give rise a strong NOE. Now, you get many more corroboratory NOEs. So the
hydrogen at the 3 position, for example, is cis to the alkene group and they [inaudible]
an NOE and we see that NOE over here. So you're starting to get pieces of the molecule sewn
together on not only the stereochemistry but also the conformation of the molecule, the
shape of the molecule. Remember I told you I have a very simple minded view about medium
sized rings. I say always start with a cyclohexane and go ahead you can sort of think of a cyclohexane
and perturb it I mentioned early on you're going to get some seven membered rings and
you can think of it kind of like an extended cyclohexane. We see this here in the seven
membered ring. The seven membered ring puckers and so the hydrogen at the 1 1 position and
one of the hydrogens at the 8 position are basically like diaxial hydrogens to each other.
And we see that very nice NOE over here. Remember how I said you can see NOEs on alkenes, and
we see this NOE here between proton 5 and 15 on the alkene. So this is really a beautiful
data set because it gives us information on the conformation and stereochemistry of the
molecule and you can then imagine building a model looking at your distances, saying
does this making sense, looking at your dihedral angles, and saying ok, are we seeing coupling
behavior here and coupling constants that match this, is everything consistent with
this model? Could there be any other stereochemistry which could be consistent with the data? Could
there be any other conformation that could be consistent wit h the data? And that's one
of the reasons that modeling and NMR work so well together. Alright, that's what I'd
like to say for today. We'll talk about, I think, the [inaudible] experiment next time
and we get to add that to our repertoire."