Name: 高速で簡単な正弦関数の近似 (Fast and Simple Approximation of Sine Function)
Uploaded: 2021-01-14T10:13:31.000Z
Duration: 11 min 22 s
Description: VoiceTubeの動画で発音を聞きながら英語表現を覚えよう！学べる英語：

Hello, A short video this week showing fast and simple approximation off the sine function.

If you're watching this video, I'm going to assume you've already searched Google for approximations of the sine function on a well aware off the several techniques that are the people use for different platforms.

程度の副詞

So I'm going to leave all of the caveats and the use cases off this approach to the end of the video on Just get stuck in with the guts of it Now.

Now, if you've watched any of my previous videos on sound synthesis, you'll know that we use the sine function a lot.

And it's usually used in this sort of format, where we take the volume on times the sign off to pi times the frequency off, the sound that we want to play times time on.

This is great when you have a processing architecture that has the facilities to do these functions.

However, my plan is, to my great some of the synthesis code to an embedded systems platform that doesn't have in silicon sign computation.

It also has a reasonably low clock frequency, so I need something that's fast and simple and because it's audio synthesis on approximation to sign is sufficient.

So I'm going to start just by defining the scope off the sine function with China's Approximate on.

The assumptions I'm going to make is that the frequency is always greater than or equal to zero on.

The time is always greater than or equal to zero.

So the final form of R sine function it's going to be simply Weikel Sign of X, where X must be greater than or equal to zero on, of course, why?

Our output is going to be from minus 12 plus one.

For the uninitiated, this is a sine wave.

And here we've got it crossing the axis at pie two pi three pie.

In fact, it'll do that forever and ever and ever, and he goes on and on and this is ah, period is city and so are approximation will also need to handle.

This period is city and that can be quite complex.

Now, assuming we're using floating point, one way to handle the period of steel would be to use something along the lines of a floating point module is function which would take our ex input on dhe.

We could modulate that by two pi, which of course means for every value over two.

Pi wraps around to zero, so we can use the basically the remainder as the index into our approximation function.

Later on, however, this function is complex, requiring a floating point divide on it may not be supported on all platforms, and I think there's a better way to do this and what I'm going to do instead is normalized the input to between zero and one.

Of course, by dividing it by two pi in this case, I want to keep it no divides because they're usually quite complicated to do so.

I'm going to multiply it by a constant one over to pie.

So this means now to pi is equal to one on zero is equal to zero, and pi is equal to 1/2 on instead of requiring us to do some arbitrary module is to some complex number like this.

Instead, we can simply hack using and floating point to interject conversion so we can take our normalized value on subtract from it, the interview value instead, so this will always give us a remainder between zero and one on just in case your language doesn't support this.

It's the equivalent of using, say the floor function.

If I graph what this looks like, we'll see its remains a PPE sine function.

But it looks like a high frequency on here.

After student on it, we can see the original sine wave in the background.

And the new Weikel signed two pi x here where the input of exits scaled by one over to pie.

We can see it crosses now at one on half and so forth along.

So now we've got this easy way of calculating the remainder without using the floating point module is I'm going to show to approximations.

I'm going to start off with a quadratic approximation to sign.

I know that my roots for at least one off the parabolas is zero and zero point fight.

So let's just start with a very basic quadratic calculation with the route at zero on a route at 00.5.

First thing I can say is it's upside down.

So I thought minus sign in there just to invert it the right way up on de so we can see it crosses now at the same places, but it needs some scaling.

I'm just gonna take a guess at the scaling on will say 10 or it's not quite enough.

So let's try 20 looks a bit too much to try somewhere in the middle.

Well, that one looks good, so let's just quickly zoom and then we see it's absolutely perfect, so it gives us a value up to a maximum off one that's handled the positive side off the sine wave.

Let's now look at a quadratic equation for the negative side, so we know that we've got a scaling factor already, and we know that we don't need it to be minus 16.

This time, probably 16 will do because it's the problem.

But our roots have changed, so now it's, Ah, no 0.5 on one.

So using two parabolas, we can roughly approximate the silent would see.

It doesn't perfectly follow the purple sine wave in the background, But you know what?

It's probably good enough for audio synthesis, and we can decide which equation to use based on the input value of X.

And if it's less than no 0.5, we use our negative crapola.

Let's just have a look at the numbers here.

So if we just copy over our first half, which was minus 16 Next take zero on X take no 0.5 routes.

And if we ah, just tidy this up a little bit, we've got minus 16 Exc word.

Take zero x Take no 0.5 x on the constant disappears.

We fill that out now to be 16 minus 16 x squirt.

Uh, take eight x And programmers get very excited when they see sixteens and eights and fours and twos because it usually means to some scope for some bit field manipulation to more optimized the mathematics involved.

Now we're doing this all in floating point.

But if I did want to convert this to a fixed point, of course, multiplied by 16 is the equivalent off shifting?

Ah, four bits on multiplying by eight Is the equivalent off shifting by three bits.

So there's potential for optimization here.

Let's also consider the other half of our problem which was 16 x take no 160.5 on X, take one.

If we expand this out again, we've now got Exc word Take 0.5 x take one X plus half.

Now I'm not going to group up the 0.5 and one for exactly the same reasons as labeled both because if we draw this out now by multiplying everything by 16 we get our 16 exc word.

Take eight x, take 16 x plus eight And again, we remained with co efficiency, which are multiples off too.

Here I've drawn out the pseudo code for approximate sine function.

I'm going to assume that we're using 32 bit floats for all of this.

And here we can see that I, first of all, scale the input to normalize it between zero and one eye.

Then do this nice way of doing ah, module iss just by taking the interview proportion away from the input on.

It's just then a question off, making a decision between which probably use whether we want the first half of the second half.

So here I've overridden the sine function in my synthesizer with the approximate sine function.

I'm going to play it and we'll have a listen.

So this is what a sine wave sounds like in this system.

Now, if I removed the sign and replace it with our approximation, it's not a bad sign way.

It does actually sound like a little bit of a square wave.

And if we look at the grafts, we can see why are approximation.

The black line is always larger than the actual sine wave itself.

It bulges out, so it's approaching a square wave very slightly.

That said, I think it's quite a good approximation now.

I'm sure there'll be some program is out there that really don't like having a branch condition in the middle of their continuous function approximation.

One way to do this would be to use an approximation that has three routes instead.

So a cubic on, I suppose it would look something like this so we would have y equals X minus zero, because we know that's one of our roots we know.

The next route is X minus no 0.5, which would be equivalent to pie in our normalize space on X minus one.

Let's take this over to the graphing platform and have a look.

Second route is at North 00.5 on our third route is at war.

We could see the roots are fine, but again, we've got a scaling issue.

I'm sure that's a mass purists out there that might be able to work this out.

So somewhere between the in fact, I know it turns out that 785 actually gives us a precise one for the output.

Using exactly the same period is city calculator that were used for the quadratic.